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Ostrovityanka [42]
3 years ago
14

Help me please someone.

Mathematics
2 answers:
GaryK [48]3 years ago
8 0

Answer:

Isolate x by multiplying by 4 to each side of the inequality

Step-by-step explanation:

You have x in a fraction, and you want to have x by itself on one side of the equation. In this case, you need to multiply by 4 to each side of the inequality to cancel the 4 on the left hand side of the inequality and leave x on its own. The final inequality is x>52.

If I helped, a brainliest answer would be greatly appreciated!

Free_Kalibri [48]3 years ago
5 0

Answer:

divide by 4 from each side

Step-by-step explanation:

\frac{x}{4} > 13

÷4    ÷4

x>13÷4

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I don’t understand how to find the height
ANTONII [103]

Answer:

<u>height</u><u>,</u><u> </u><u>x</u><u> </u><u>is</u><u> </u><u>2</u><u>3</u><u>5</u><u> </u><u>ft</u>

Step-by-step explanation:

From trigonometric ratios:

\cos( \theta)  =  \frac{adjacent}{hypotenuse}

but:

\theta = 90 \degree - 36 \degree \\  \theta = 54 \degree

adjacent is x

hypotenuse is 400 ft

\ \cos ( 54 \degree)  =  \frac{x}{400}  \\  \\ x = 400 \ \cos (54 \degree)  \\ x = 235 \: \:  feet

8 0
3 years ago
Read 2 more answers
If a triangle is 12 inches high and has a 20 inch long hypotenuse then how wide is it?
Ber [7]

Answer:

The triangle should be 16 inches wide.

Step-by-step explanation:

\text {Use the Pythagorean Theorem to solve for the leg.}\\a^2 + b^2 =c^2

What we know:

  • One of the legs measures 12 inches.
  • The hypotenuse is 20 inches.

We need to solve for b. Solving for a while b is 12 would also be acceptable.

12^2 + b^2 = 20^2  \text {  OR  }   a^2 +12^2=20^2

We will use the first equation.

12^2 + b^2 = 20^2\\12 * 12 = 144\\20 * 20 = 400\\\\\boxed {144 + b^2 = 400}

\text {Subtraction property of equality: }\\144-144+ b^2 = 400-144\\\boxed {b^2 = 256}\\\\\text {Take the square root of 256: }\\\sqrt{256}=\sqrt{b^2} \boxed {16 = b}

The triangle should be 16 inches wide.

3 0
3 years ago
Several polynomial functions are graphed. Which graph displays a polynomial function with all even exponents?
BartSMP [9]
A polynomial function with all even exponents is so-called even function.
Even functions are symmetric across the y-axis.
Answer:  Only one that is symmetric across the x-axis is the function C ).
7 0
3 years ago
Read 2 more answers
Using adding and substitution to find the value of x for the set of equations x-y=120 x+y=150
Ronch [10]
X= 135 and Y = 15. Hope that helps!
5 0
3 years ago
Is the set \mathbb{Z} a group under the operation a*b = a - b + ab ? Justify your answer.
Daniel [21]

Answer:

Step-by-step explanation:

Given that *is the binary operation in the sets of integers.

a*b = a - b + ab

closure: a-b+ab is again an integer belongs to Z.  Hence closure is true.

Associativity: a*(b*c) = a*(b+c-bc)\\= a-b-c+bc+ab+ac-abc\\= a-b-c +ab+bc+ca-abc

(a*b)*c=(a+b-ab)*c\\=a+b-ab-c+ac+bc-abc\\

The two are not equal.  Hence this cannot be a group as associtiavity does not hold good.

7 0
2 years ago
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