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Ulleksa [173]
3 years ago
12

Draw a Triangle whose tangent is 2. Find the values of the other five trigonometric functions

Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

you gonna answer it

Step-by-step explanation:

Because that's yours book

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What is 3/ 4 of 6 / 7?
Vika [28.1K]
3/4 of 6/7.    The of means multiplication.

= 3/4  *  6/7.  2 into 4 is 2 and 2 into 6 is 3.
 = 3/2 * 3/7    No other number can divide, so we multiply out.
=9/14

That's the answer.
6 0
3 years ago
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Sidney skated for 1 1/10 hours last month and 8 7/10 hours this month. How many
olganol [36]

Answer:

the number of hours does sidney skate in all is 9.8 hours

Step-by-step explanation:

The computation of the number of hours does sidney skate in all is as follows:

= Last month + this month

= 1 \frac{1}{10} + 8 \frac{7}{10}\\\\= \frac{11}{10} + \frac{87}{10}\\\\= \frac{98}{10}

= 9.8 hours

Hence, the number of hours does sidney skate in all is 9.8 hours

3 0
3 years ago
A book is 21 centimeters long, how long is this in meters?
Gnesinka [82]

Answer:

0.21 meters :)

Step-by-step explanation:

4 0
3 years ago
Which line segment is drawn in the figure?<br><br> A.YZ<br> B.WY<br> C.XZ<br> D.WZ
Dima020 [189]
The line segment shown in the figure is C. XZ. A line segment is a line that is bounded by 2 endpoints, hence the line is not infinite. As shown in the figure, only points X and Z are visibly connected. There are no visible lines connecting the other points together.
6 0
3 years ago
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Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

6 0
3 years ago
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