Answer:
x = 2 x = -6
Step-by-step explanation:
2 (x+2) ^2-4=28
Add 4 to each side
2 (x+2) ^2-4+4=28+4
2 (x+2) ^2= 32
Divide by 2
2/2 (x+2) ^2=32/2
(x+2)^2 = 16
Take the square root of each side
sqrt((x+2)^2) =±sqrt( 16)
x+2 = ±4
Subtract 2 from each side
x+2-2 = -2±4
x = -2±4
x = -2+4 and x = -2-4
x = 2 x = -6
Answer:
C. 275.88 m squared
24.2 * 11.4 = 275.88 m squared
Answer: 12 minutes
Step-by-step explanation:
Two rates for hoses A and B. FP is the Fish Pond.
A = 20 min/FP or (1/20)FP/min
B = 30 min/FP or (1/30)FP/min
The time in minutes, X, to fill one FP:
1FP = X*((1/20)FP/min) + X*((1/30)FP/min)
1FP = X*(1/20+1/30)FP/min
1FP = X*(2.5/30)FP/min
X = 12 minutes
Let x the maximum speed of the plane and y be the speed of the wind.
We know that:
1)Distance = speed x time
2) if the head wind is y, then the resulting speed is x-y (against the wind)
3) if the tail wind is y, then the resulting speed is x+y (with the wind)
1) and 2): 2400 = (x-y).(6) or 6x-6y = 2400
1) and 3): 2400 = (x+y).(5) or 5x+5y = 2400
Hence the system of 2 equation:
6x - 6y = 2400
5x + 5y = 2400.
Solving it gives x = 440 mi/h and y = 40 mil/h
Then the speed of the plane with no wind is 440 km/h
Answer:
the ball is on the ground after 3 seconds right so it would still be on the ground
Step-by-step explanation:
