Standard Form : f (x) = a(x - h)2 + k
Where in this equation (H,K) is the vortex of the parabola
<u>and there are four other ways to solving these quadratic</u>
1. Factoring
2. Completing the square
3. Your quadratic formula ( f (x) = a(x - h)2 + k )
4. Graphing
Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
Answer:
8 cups of hot chocolate
Step-by-step explanation:
y = log5 ( x + 2 )
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Answer:
A≈110.11
using formula 1/4
Step-by-step explanation:
