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3 years ago

15

At what point does y = 3x -2 intercept :

1 answer:

bezimeni [28]3 years ago

5 0

Y axis= -2
x axis= 2/3

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N + M? N = 9.1 7.9 -2.4 0.2 -5.8 1.4 and M= 8.2 -0.6 -2.8 -1.8 -2.4 -6.1

Ierofanga [76]

Answer:

$N + M = \begin{pmatrix}17.3&7.3\\ -5.2&-1.6\\ -8.2&-4.7\end{pmatrix}$

Step-by-step explanation:

$\begin{pmatrix}9.1&7.9\\ -2.4&0.2\\ -5.8&1.4\end{pmatrix} +\begin{pmatrix}8.2&-0.6\\ -2.8&-1.8\\ -2.4&-6.1\end{pmatrix} =\begin{pmatrix}9.1+8.2&7.9-0.6\\ -2.4-2.8&0.2-1.8\\ -5.8-2.4&1.4-6.1\end{pmatrix}$

Then

$\begin{pmatrix}9.1&7.9\\ -2.4&0.2\\ -5.8&1.4\end{pmatrix} +\begin{pmatrix}8.2&-0.6\\ -2.8&-1.8\\ -2.4&-6.1\end{pmatrix} =\begin{pmatrix}17.3&7.3\\ -5.2&-1.6\\ -8.2&-4.7\end{pmatrix}$

4 0

2 years ago

The supply curve for steel is 90x−y=−50. The demand curve is 10x+y=200. x is quantity in thousands of metric tons y is price in

ivolga24 [154]

Answer:

The intersection point of the two curves is $(x,y) = \left(\frac{3}{2}\,kton.m, 185\,USD \right)$ .

Step-by-step explanation:

From statement we get the following equations:

Supply curve

$90\cdot x - y = -50$ (1)

Demand curve

$10\cdot x + y = 200$ (2)

Where:

$x$ - Quantity, measured in thousands of metric tons.

$y$ - Price, measured in US dollars per metric tons.

If we add both equations, then we find that quantity is:

$(90\cdot x -y )+(10\cdot x +y) = -50+200$

$100\cdot x = 150$

$x = \frac{3}{2}\,kton.m$

Then, we finally find the price by substituting on (2):

$y = 200-10\cdot \left(\frac{3}{2} \right)$

$y = 200-15$

$y = 185\,USD$

The intersection point of the two curves is $(x,y) = \left(\frac{3}{2}\,kton.m, 185\,USD \right)$ .

5 0

3 years ago

Solve for X (8th Grade Math)

svetlana [45]

Answer:

X=10

Step-by-step explanation:

180-116=64

4x+7x+6+64=180

11x+70=180

11x=110

x=10

3 0

3 years ago

1. Gabriel has a candy box containing 9 chocolates candies and 12 lollipops. If he choose 2 of them at random.

adoni [48]

<u>Question</u> :

Gabriel has a candy box containing 9 chocolates candies and 12 lollipops. If he choose 2 of them at random.

a) What is the probability that he gets 2 lollipops?

b) What is the probability that he gets 2 chocolates?

c) What is the probability that he gets at least 1 lollipop and 1 chocolate?

<u>Answer</u>:

First we need to calculate the total no. of items. In this case it is the no. of chocolate candies + the no. of lollipops which is, 9 + 12 = <u>21</u>.

Now we can solve the questions.

a) P (2 lollipops) = <u>2/21.</u>

b) P (2 chocolates) = <u>2/21.</u>

c) P (at least 1 lollipop & 1 chocolate) = <u>2/21</u>.

Note : P(x) is read as probability of getting x is....

7 0

3 years ago

Read 2 more answers

What are the solutions to the nonlinear system of equations below? check all that apply

Arisa [49]

E. (1, -5)
f. (-1, 5)

This can be solved by substituting -5x for y in the second equation.

5 0

3 years ago