Given that the equation of the line is:
y=-18x-2
the equation is in the form of y=mx+c, where m is the slope. Thus the slope of equation is -18. The line perpendicular to this equation has a slope of 1/18, hence the equation will be given by the formula:
m(x-x1)=y-y1
given that the line passes through point (-2,-3) the equation of the line will be:
1/18(x--2)=y-(-3)
1/18(x+2)=y+3
simplifying this gives us:
y=1/18x+1/9+3
y=1/18x6+3 1/9
I would say this is the answer:
You can put this solution on YOUR website!
<span>a right triangle has 2 legs and a hypotenuse.
the hypotenuse is opposite the 90 degree angle.
the 2 legs are opposite the other angles of the triangle.
if you know 2 of the dimensions then you simply use the formula to solve for the remaining dimension.
assume one of the legs is equal to a and the other leg is equal to b and the hypotenuse is equal to c.
then the formula is:
c^2 = a^2 + b^2
suppose you know the value of a and b
you substitute for a and b in the equation and solve for c.
assume a = 6 and b = 8
the formula becomes:
c^2 = 6^2 + 8^2 = 36 + 64 = 100
now you take the square root of both sides of the equation to get:
c = sqrt(100) = 10
now suppose you knew that c was equal to 10 and a was equal to 6.
your equation of:
c^2 = a^2 + b^2 becomes:
10^2 = 6^2 + b^2 which becomes:
100 = 36 + b^2
you subtract 36 from both sides of the equaton to get:
100 - 36 = b^2
you simplify to get:
64 = b^2
you take the square root of both sides of the equation to get:
8 = b
Hope I could Help! Can I have Brainliest!</span>
n(A-B) denotes elements which are in A but not in B
n(Au B) denotes elements in A and B
n(AnB) denotes elements that are common in A and B
Now I will add one more set
n(B-A) which denotes elements in B but not in A
So, n(AuB) = n(A-B) + n( B-A) +n(AnB)
70 = 18 +n(B-A) + 25
70 = 43 + n(B-A)
n(B-A) = 70-43
n(B-A) = 27
So, n(B) = n( B-A) + n( AnB)
= 27+25
= 52
Answer:
-1/2=x
Step-by-step explanation:
-9 + x = 5x - 7
-x -x
-9=4x-7
+7 +7
-2=4x
-2/4 =4x/4
-1/2=x
