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levacccp [35]
3 years ago
6

The speed of a wave in the string is 16.2ms. The mass per unit length of the string is 0.3ms calculate tension in the string

Chemistry
1 answer:
liberstina [14]3 years ago
6 0

Answer:

The tension in the string is 78.73 N.

Explanation:

The tension in the string can be determined from the expression;

v = \sqrt{\frac{T}{m} }

where: v is the speed of the wave in the sting, T is the tension in the string and m is the mass per unit length of the sting.

Given that: v = 16.2 m/s, and m = 0.3 kg/m.

Then;

16.2 = \sqrt{\frac{T}{0.3} }

Square both sides to have,

(16.2)^{2} = \frac{T}{0.3}

T = (16.2)^{2} x 0.3

  = 252.44 x 0.3

  = 78.732

T = 78.732 N

The tension in the string is 78.73 N.

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CaCO₃ partially dissociates in water as Ca²⁺ and CO₃²⁻. The balanced equation is,
                       CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Initial                Y                   -                 -
Change           -X                  +X              +X
Equilibrium      Y-X                 X                X

Ksp for the CaCO₃(s) is 3.36 x 10⁻⁹ M²

                Ksp = [Ca²⁺(aq)][CO₃²⁻(aq)]
3.36 x 10⁻⁹ M² = X * X
3.36 x 10⁻⁹ M² = X²
                    X = 5.79 x 10⁻⁵ M

Hence the solubility of CaCO₃(s) = 5.79 x 10⁻⁵ M
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Molar mass of CaCO₃ = 100 g mol⁻¹

Hence the solubility of CaCO₃ = 5.79 x 10⁻⁵ mol/L x 100 g mol⁻¹
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