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Firlakuza [10]
3 years ago
12

If a stone with an original velocity of 0 is falling from a ledge and takes 8 seconds to hit the ground what is the final veloci

ty of the stone
Chemistry
1 answer:
ziro4ka [17]3 years ago
5 0
Also 0 as it hits the ground and stops
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An atom with 4 protons, 5 neutrons, and 4 electrons has an atomic mass of _____ amu. (Enter a whole number.)
STatiana [176]
I believe it would be the sum of protons & neutrons which equals 9 amu....
7 0
3 years ago
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What are the coefficients of the compounds after balancing the following equation and what type of reaction is this?
Oksana_A [137]

The coefficient of Fe would be 2, the coefficient of Cl2 would be 3, while the coefficient of FeCl2 would be 2.  

The balanced equation of the reaction would be as follows:

2Fe(S) + 3Cl_2 ---> 2FeCl_3(S)

Thus, the coefficients of Fe, Cl2, and FeCl3 respectively would be 2, 3, and 2.

In other words, 2 moles of Fe require 3 moles of Cl2 to produce 2 moles of FeCl3 in a complete reaction.

More on balancing chemical equations can be found here: brainly.com/question/8062886?referrer=searchResults

4 0
3 years ago
Please please help me!! It needs to be turned in in a few minutes!
rjkz [21]
I think the answer is thermal!
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5 0
3 years ago
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The six kingdom system was designed
KonstantinChe [14]

Answer:

Prokaryotes is the answer

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3 0
4 years ago
Please help, and if you could also give me a step by step that would be awesome!!
const2013 [10]

Answer:

4.4 g

Explanation:

Step 1: Write the balanced equation

Cu + 4 HNO₃ ⇒ Cu(NO₃)₂ + 2 NO₂ + 2 H₂O

Step 2: Calculate the moles corresponding to 3.2 L of NO₂ at STP

At standard temperature and pressure, 1 mole of NO₂ occupies 22.4 L.

3.2 L × 1 mol/22.4 L = 0.14 mol

Step 3: Calculate the moles of Cu needed to produce 0.14 moles of NO₂

The molar ratio of Cu to NO₂ is 1:2. The moles of Cu needed are 1/2 × 0.14 mol = 0.070 mol.

Step 4: Calculate the mass corresponding to 0.070 moles of Cu

The molar mass of Cu is 63.55 g/mol.

0.070 mol × 63.55 g/mol = 4.4 g

5 0
3 years ago
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