The compression factor based on the information given is 0.083.
<h3>How to calculate the compression factor?</h3>
The way to calculate the compression factor goes this:
V(ideal) = RT/P
= (0.0821 × 250)/15
= 1.368
V(real) will be:
= V(ideal)/12
= 1.368/12 = 0.114
The compression factor will be:
= 1.368/(12 × 1.368)
= 0.083
Therefore, the compression factor is 0.083.
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HNO₃ + H₂S → S + NO + H₂<span>O
Assign Oxidation Number:
L.H.S R.H.S
N in HNO</span>₃ = +5 +2 = N in NO
S in H₂S = -2 0 = S in S
Write Half cell Reactions:
Reduction Reaction:
3e⁻ + HNO₃ → NO -------(1)
Oxidation Reaction:
H₂S → S + 2e⁻ -------(2)
Multiply eq. 1 with 2 and eq. 2 with 3 to balance electrons.
6e⁻ + 2 HNO₃ → 2 NO
3 H₂S → 3 S + 6e⁻
Cancel e⁻s,
______________________________
2 HNO₃ + 3 H₂S → 2 NO + 3 S + H₂O
Balance Oxygen Atoms by multiplying H₂O with 4, Hydrogen atoms will automatically get balance.
2 HNO₃ + 3 H₂S → 2 NO + 3 S + 4H₂O
Answer:
(β⁺), and another one is 01e
Answer: It is approximately 24.985837
