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avanturin [10]
4 years ago
10

I need help FAST ASAP

Chemistry
1 answer:
kiruha [24]4 years ago
6 0
In this item, we are simply to find the ions that may bond and are able to form a formula unit. We are also instructed to give out their name. There are numerous possible combinations of ions to form a compound. Some answers are given in the list below.

1.  Na⁺     ,    Cl⁻    , NaCl   ---> sodium chloride (this is most commonly known as table salt)

2. C⁴⁺       , O²⁻     , CO₂  ---> carbon dioxide

3. Al³+     , Cl⁻       , AlCl₃   ----> aluminum chloride

4. Ca²⁺     , Cl⁻     , CaCl₂    ---> calcium chloride

5. Li⁺        , Br⁻      , LiBr       ---> lithium bromide

6. Mg³⁺     , O²⁻      , Mg₂O₃   ----> magnesium oxide

7. K⁺        , I⁻          , KI   ---> potassium iodide

8. H⁺        , Cl⁻        , HCl  --> hydrogen chloride

9. H⁺        , Br⁻         , HBr ----> hydrogen bromide

10. Na⁺    , Br⁻         , NaBr   ---> sodium bromide
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99% of matter that makes up living organisms consists of how many elements?
DiKsa [7]

Answer:

h2o or air

Explanation:

6 0
4 years ago
If an atom has no electric charge, what can be said about the number of protons and electrons it contains?
vitfil [10]

then the electrons and protons would have a even amount of negetive electric charges

8 0
3 years ago
What is the name of this compound?<br><br> C6H6-<br> C=O-<br> H
ipn [44]

Answer: Benzaldahyde

Explanation: the C₆H₅- represents the substituted benzene ring and the

CHO should represent the functional group of aldehyde

8 0
3 years ago
Read 2 more answers
Which pair has identical electron configurations?
Thepotemich [5.8K]

Identical electron configurations : K⁺ and Cl⁻

<h3>Further explanation  </h3>

In an atom, there are levels of energy in the shell and sub-shell  

This energy level is expressed in the form of electron configurations.  

Charging electrons in the sub-shell uses the following sequence:  

<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  </em>

  • S²⁻ and CI

S²⁻ : [Ne] 3s²3p⁶

Cl : [Ne] 3s²3p⁵

  • K⁺ and CI⁻

K⁺ : 1s² 2s² 2p⁶ 3s² 3p⁶

Cl⁻ : 1s² 2s² 2p⁶ 3s²3p⁶

  • S and Ar

S :[Ne] 3s²3p⁴

Ar : [Ne] 3s²3p⁶

  • Cl⁻ and K

Cl⁻ : 1s² 2s² 2p⁶ 3s²3p⁶

K : 1s² 2s² 2p⁶ 3s² 3p⁶4s¹

6 0
3 years ago
20 ML of a gas at 200 K is heated until the new volume is 55ML what is the final temperature of the gas
MrRa [10]

Answer:

T2 = 550K

Explanation:

From Charles law;

V1/T1 = V2/T2

Where;

V1 is initial volume

V2 is final volume

T1 is initial temperature

T2 is final temperature

We are given;

V1 = 20 mL

V2 = 55 mL

T1 = 200 K

Thus from V1/T1 = V2/T2, making T2 the subject;

T2 = (V2 × T1)/V1

T2 = (55 × 200)/20

T2 = 550K

8 0
3 years ago
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