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3 years ago

I need help FAST ASAP

Chemistry

1 answer:

kiruha [24]3 years ago

6 0

In this item, we are simply to find the ions that may bond and are able to form a formula unit. We are also instructed to give out their name. There are numerous possible combinations of ions to form a compound. Some answers are given in the list below.

1. Na⁺ , Cl⁻ , NaCl ---> sodium chloride (this is most commonly known as table salt)

2. C⁴⁺ , O²⁻ , CO₂ ---> carbon dioxide

3. Al³+ , Cl⁻ , AlCl₃ ----> aluminum chloride

4. Ca²⁺ , Cl⁻ , CaCl₂ ---> calcium chloride

5. Li⁺ , Br⁻ , LiBr ---> lithium bromide

6. Mg³⁺ , O²⁻ , Mg₂O₃ ----> magnesium oxide

7. K⁺ , I⁻ , KI ---> potassium iodide

8. H⁺ , Cl⁻ , HCl --> hydrogen chloride

9. H⁺ , Br⁻ , HBr ----> hydrogen bromide

10. Na⁺ , Br⁻ , NaBr ---> sodium bromide

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Pb3(po4)2 compound name

ch4aika [34]

Answer:

Lead phosphate

Explanation:

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1 year ago

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Zn + AgCI - ZnCl2 + - Ag HELPPP?

garik1379 [7]

Answer:

Explanation: Zn (s) + 2 AgCl (s) ⇒ ZnCl2 (s) + 2 Ag(s)

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8 0

2 years ago

If the dosage for a medication is 225mg/lb, how many grams should a 25-lb child be given?

Oksanka [162]

Answer:

5.625 grams

Explanation:

Start your equation with what you have been given. Place the units you need in your answer on the right side of the equal sign.

225mg

----------- X ----------- X ------------- = ? g

Now start to fill in your equation and use a conversions to get rid of the units you don't want. Convert mg into grams first. The child's weight (25 lb) is placed over 1 just to get the equation lined up properly so you can see how the units cancel out.

225 mg 1 g 25 lb 5.625 g

--------------- X --------------- X ------------- = ---------------

lb 1000 mg 1 1

The lb on the top and bottom cancel each other out and you are left with just grams. Even though it is over one, that is the same at just 5.625 grams.

3 0

2 years ago

Determine the resulting pH when 75 mL of 0.05M HBr is reacted with 74 mL of 0.075 M KOH

Sunny_sXe [5.5K]

Answer:

pH = 12.08

Explanation:

H⁺ + OH⁻ → H₂O

First we calculate how many moles of each substance were added, using the given volume and concentration:

HBr ⇒ 0.05 M * 75 mL = 3.75 mmol HBr

KOH ⇒ 0.075 M * 74 mL = 5.55 mmol KOH

As HBr is a strong acid, it dissociates completely into H⁺ and Br⁻ species. Conversely, KOH dissociates completely into OH⁻ and K⁺ species.

As there are more OH⁻ moles than H⁺ moles (5.55 vs 3.75), we calculate how many OH⁻ moles remain after the reaction:

5.55 - 3.75 = 1.8 mmoles OH⁻

With that number of moles and the volume of the mixture, we calculate [OH⁻]:

[OH⁻] = 1.8 mmol / (75 mL + 74 mL) = 0.0121 M

With [OH⁻], we calculate the pOH:

pOH = -log[OH⁻] = 1.92

With the pOH, we calculate the pH:

pH = 14 - pOH

pH = 12.08

6 0

2 years ago

Lighters are usually fueled by butane (c4h10). when 1 mole of butane burns at constant pressure, it produces 2658 kj of heat and

Leokris [45]

Answer:

ΔE = -2661 KJ/mole

ΔH = -2658 KJ/mole

Explanation:

ΔH = q - PΔV

ΔE = q + w

First, to find ΔE:

The reaction PRODUCES 2658 kJ of h (q), and does 3 kJ of work (w).

2658 kJ(q) + 3 kJ(w) = 2661 kJ, BUT the reaction PRODUCES heat, which means ΔE is negative.

ΔE = -2661 KJ/mole

Second, to find ΔH:

ΔH = q - PΔV

ΔH = 2658 kJ(q) - PΔV

Now, the question states that butane burns at a constant pressure; that just translates to the pressure of the reaction is equal to 0.

ΔH = 2658 KJ(q) - (0)ΔV

ΔH = 2658 KJ - 0

ΔH = 2658 kJ, BUT, like before, the reaction PRODUCES heat, which also mean ΔH is negative.

ΔH = -2658 KJ/mole

I hope this helped! Have a nice week.

5 0

2 years ago