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Neporo4naja [7]

3 years ago

11

Joey has $27. He wants to a cake for $25 before tax. Sales tax is 8%. Does Joey have enough to buy the cake? How much is the cak

e with tax?

2 answers:

Black_prince [1.1K]3 years ago

8 0

Yes, 8 percent of 25 is 2 so he has exactly enough to pay.

viktelen [127]3 years ago

5 0

Answer:

yes

Step-by-step explanation:

$25*8%

25*0.08=2

25+2=27

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coldgirl [10]

Answer:

$6.75 and $4.50

Step-by-step explanation:

a) <u>Jamal spent:</u>

2x

<u>Isaiah spent:</u>

3 (x - 2.25)

<u>The equation is:</u>

2x = 3(x - 2.25)

b) <u>Solving the equation</u>

2x = 3x - 6.75
3x - 2x = 6.75
x = 6.75

c) <u>Jamal's items cost </u>

$6.75 each

<u>Isaiah's items cost </u>

$6.75 - $2.25 = $4.50 each

7 0

3 years ago

Johnny spent $28.50 at a parking garage in downtown Asheville. The garage

just olya [345]

Answer:3 hour

Step-by-step explanation:

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8 0

3 years ago

Correct the error. What should the line actually be?

Natali5045456 [20]

Answer:

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Step-by-step explanation:

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3 0

2 years ago

Five friends equally shared half of one large pizza and 1/4 of another large pizza. what fraction of each pizza did each friend

attashe74 [19]

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3 0

3 years ago

(1/4)^3z-1 =16^z+2*64^z-2<br><br> Z=___<br><br> Please help

wariber [46]

Answer:

Z = 0.198877274

Step-by-step explanation:

$(\frac{1}{4})^{3z-1} = 16^z + 2*16^{z-2}\\4^{1-3z} = 4^{2z} + 4^{\frac{1}{2}}*4^{2z-4}\\4^{1-3z} = 4^{2z} + 4^{2z-4+\frac{1}{2}}\\4^{1-3z} = 4^{2z} + 4^{2z-\frac{7}{2}}\\4^{1-3z} = 4^{2z} *(1+ 4^{-\frac{7}{2}})\\4^{1-3z} = 4^{2z} *(1+ 2^{-7})\\4^{1-3z} = 4^{2z} *(1+ \frac{1}{128} )\\4^{1-3z} = 4^{2z} *(\frac{129}{128} )\\Taking\;\; Logarithm\;\; with\;\; base\;\; 4\\Log_4(4^{1-3z}) = Log_4(4^{2z}) + Log_4(\frac{129}{128})\\1-3z = 2z + 0.005613627712 \\5z = 0.994386372\\z = 0.198877274$

Hence, the value of Z = 0.198877274

8 0

3 years ago

Read 2 more answers