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QveST [7]
3 years ago
5

Find the range of the function f(x)=

%20%7D%7B2x%20-%201%7D%20" id="TexFormula1" title=" \frac{ {x}^{2} + 3x + 5 }{2x - 1} " alt=" \frac{ {x}^{2} + 3x + 5 }{2x - 1} " align="absmiddle" class="latex-formula">


​
Mathematics
2 answers:
natali 33 [55]3 years ago
6 0

Rewrite the numerator as

<em>x</em> ² + 3<em>x</em> + 5 = (<em>x</em> - 1/2)² + 4 (<em>x</em> - 1/2) + 27/4

Then

(<em>x</em> ² + 3<em>x</em> + 5) / (2<em>x</em> - 1) = 1/2 × (<em>x</em> ² + 3<em>x</em> + 5) / (<em>x</em> - 1/2)

… = 1/2 × ((<em>x</em> - 1/2)² + 4 (<em>x</em> - 1/2) + 27/4) / (<em>x</em> - 1/2)

… = 1/2 × ((<em>x</em> - 1/2) + 4 + 27 / (4 (<em>x</em> - 1/2)))

… = 1/2 <em>x</em> + 7/4 + 27 / (8 (<em>x</em> - 1/2))

which clearly has a non-removable singularity at <em>x</em> = 1/2, which is to say this function has a domain including including all real numbers except 1/2.

For every number other than <em>x</em> = 1/2, the function takes on every possible real numbers, since 1/2 <em>x</em> + 7/4 alone takes on all real numbers.

So:

domain = {<em>x</em> ∈ ℝ | <em>x</em> ≠ 1/2}

range = {<em>x</em> ∈ ℝ}

Oxana [17]3 years ago
5 0
Photo math is very helpful with those type of problems
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Step-by-step explanation:

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