Answer:
6y^3x^3-y^2x^3
Step-by-step explanation:
There are three elements in that set.
Please, do not post more than 1 or 2 questions at a time. Out of courtesy I will address one of your six questions here:
<span>2x + 4 = 3(x – 2) + 1
You are to solve this for x.
1) perform the multiplication: </span><span>2x + 4 = 3x - 6 + 1
2) combine like terms: 4+6-1 = x
3) solve for x: x = 11
4) check: Is 2(11) + 4 = 3(11-2) + 1 true?
Is 22+4 = 33-6 true? NO. Try again, looking for the mistake:
</span><span>2x + 4 = 3(x – 2) + 1 => 2x + 4 = 3x - 6 + 1
4 = x - 5
9 = x
Check: Is 2(9) + 4 = 3(9-2) + 1 true? Is 18+4 = 22 true? YES.
The solution to #1 is x = 9 (answer).
Submit your other questions separately, please.
</span>
Answer:
y>5/6
Step-by-step explanation:
5y+3>-7y+13
5y+7y>13-3
12y/12>10/12
y>5/6
This is an inequality, which shows where the variable y does or does not exist
from this we can say
y: (-infinity,5/6) (5/6, infinity]
or, y does not exist from (-infinity,5/6)
and does exist from (5/6, infinity]
