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Answer:
Step-by-step explanation:
ΔBCD is isosceles, so ∠CDB = ∠CBD = x. The sum of angles in the triangle is 180°, so you have ...
x + x + 50° = 180°
2x = 130° . . . . . . . . . subtract 50°, collect terms
x = 65° . . . . . . . divide by 2
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Triangle ABC is also isosceles, so ∠BAC = ∠BCA = y. Angle ABC is the supplement of angle x. The sum of angles in ΔABC is 180°:
y + y + (180° -x) = 180°
2y - 65° = 0 . . . . . . . . . . subtract 180°, substitute the value of x
y -32.5° = 0 . . . . . . . divide by 2
y = 32.5° . . . . . . . . . . add 32.5°
