Answer:
As per the statement:
The path that the object takes as it falls to the ground can be modeled by:
h =-16t^2 + 80t + 300
where
h is the height of the objects and
t is the time (in seconds)
At t = 0 , h = 300 ft
When the objects hit the ground, h = 0
then;
-16t^2+80t+300=0
For a quadratic equation: ax^2+bx+c=0 ......[1]
the solution for the equation is given by:
On comparing the given equation with [1] we have;
a = -16 ,b = 80 and c = 300
then;
Simplify:
= -2.5 sec and 
= 7.5 sec
Time can't be in negative;
therefore, the time it took the object to hit the ground is 7.5 sec
Answer:
find f(5) and g(5) then divide f(5) by g(5) i.e f(5)/g(5) Answer will be 25/6
We know that
if two lines are perpendicular
then
the slopes
m1*m2=-1
step 1
find the slope AB
A (0,2)
B (-3,-3)
m=(y2-y1)/(x2-x1)-----> m=(-3-2)/(-3-0)-----> m=-5/-3----> m1=5/3
step 2
find the slope CD
C (-4,1)
D (0,-2)
m=(y2-y1)/(x2-x1)-----> m=(-2-1)/(0+4)-----> m=--3/4----> m2=-3/4
step 3
multiply mi*m2
(5/3)*(-3/4)-----> -15/12
so
15/12 is not -1
therefore
AB is not perpendicular to CD
Answer:
Acute angle = 30°
Obtuse angle = 150°
Step-by-step explanation:
Method 1:
Let x represent the measurement of the obtuse angle
Obtuse angle = x
Acute angle = ⅕ of x = x/5
Thus:
x + x/5 = 180° (angels on a straight line)
Solve for x
(5x + x)/5 = 180
Multiply both sides by 5
5x + x = 180 × 5
6x = 900
x = 900/6
x = 150
Obtuse angle = 150°
Acute angle = x/5 = 150/5 = 30°
Method 2:
Since acute angle = ⅕ of the obtuse angle, therefore,
Obtuse angle = 5*acute angle
Let acute angle = x
Obtuse angle = 5x
Equation:
5x + x = 180° (angles on a straight line)
Solve for x
6x = 180
x = 180/6
x = 30
Acute angle = x = 30°
Obtuse angle = 5x = 5*30 = 150°
Answer:
Step-by-step explanation: La fórmula de la caída libre, teniendo a la altura como valor dado, sería:
donde h es la altura y g la gravedad.
Solución
h=100 metros
g=9.8m/s^2
se sustituye en la fórmula
dando como resultado
th=4.52 segundos de caída libre
