Question

A right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm. Find the

Answer 1

Answer:

The volume and the curved surface area of the solid formed is $301.71\ \text{cm}^3$ and $188.57\ \text{cm}^2$ respectively.

Step-by-step explanation:

Given that,

A right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm.

As the triangle is revolved at 8 cm it forms a cone of height 8 cm and radius 6cm.

Height, h = 8 cm

Radius, r = 6 cm

The volume of the solid formed is given by :

$V=\dfrac{1}{3}\pi r^2 h\\\\=\dfrac{1}{3}\times \dfrac{22}{7}\times 8^2\times 8\\\\=301.71\ \text{cm}^3$

The curved surface of the solid formed is :

$A=\pi rl$

l is slant height

$A=\pi r\times \sqrt{h^2+r^2} \\\\A=\dfrac{22}{7}\times 6\times \sqrt{8^2+6^2} \\\\=188.57\ \text{cm}^2$

Hence, the volume and the curved surface area of the solid formed is $301.71\ \text{cm}^3$ and $188.57\ \text{cm}^2$ respectively.