Answer:
Predominantly ,the color is due to cation Ba2+.
Explanation:
Flame Test : The flame due barium cation is Green in color.
Anions such as Cl- and SO42- slightly (very little) affects the color . Hence ,
BaCl2 and BaSO4 gives Yellow -green flame not pure green
Ba 2+ cation gives green colour because:
It has loosely bounded outermost electron (low ionisation)
It absorb energy from the flame , get excited to higher energy state. When the excited electron comes back to ground state , it emits colour of particular frequency.
When studying quantum mechanics, the de Broglie wavelength is a key idea. De Broglie wavelength is the wavelength () that is connected to an item in relation to its momentum and mass.
Typically, a particle's force is inversely proportional to its de Broglie wavelength.
Assuming that the smallest measurable wavelength in an experiment is 0.830 fm , what is the maximum mass of an object traveling at 171 m⋅s−1 for which the de Broglie wavelength is observable?
We know:
- The shortest wavelength that is detectable, λm = 0.330 fm
- the object's velocity, v = 157 m/s
According to the following equation, an object's de-Broglie wavelength solely depends on its momentum:
λ = h/p = h/m*v, where,
- h = 6.626 × 10^(−34) J⋅s
- p = mv is the object's momentum. It is based on the moving object's mass, m, and velocity, v.
By rearranging the above equation, the object's mass can be written as:
m = h/λv
The maximum mass and the minimum de Broglie wavelength of the item are inversely correlated because the two quantities are inversely proportional to one another. When we enter the values provided, we get:
m = {6.626×10^(−34) J⋅s} / {0.330 fm × 157 m/s}
≈ 1.28×10^(−20) kg
To know more about de Broglie Wavelength, click on the link below:
brainly.com/question/1601551
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