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Assoli18 [71]
4 years ago
6

A sample of the inhalation anesthetic gas Halothane, in a 500-mL cylinder has a pressure of 2.3 atm at 0°C. What will be the pre

ssure of the gas if its temperature is warmed to 37°C (body temperature)? (Hint: Which law will you apply if the volume is constant?)
Chemistry
2 answers:
STALIN [3.7K]4 years ago
8 0

Answer: 2.56atm

Explanation:

P1/T1=P2/T2

P1T2=P2T1

P2=P1T2/T1

P1=2.3atm

P2=?

T1=0+273=273k

T2=32+273=305k

P2=2.3*305/273

P2=701.5/273

P2=2.56atm

lilavasa [31]4 years ago
3 0

Answer:

The pressure will increase to a pressure of 2.6 atm

Explanation:

Step 1: Data given

Volume = 500 mL = 0.500L

Pressure = 2.3 atm

Temperature = 0°C = 273 K

Temperature is warmed to 37 °C = 310 K

Volume will stay constant

Step 2: Calculate the new pressure

p1/T1 = p2/T2

⇒with p1 = the initial pressure = 2.3 atm

⇒with T1 = the initial temperature = 0 °C = 273 K

⇒with p2 = the new pressure = TO BE DETERMINED

⇒with T2 = the new temperature = 37 °C = 310 K

2.3 atm / 273 K  = p2 / 310 K

p2 = 2.6 atm

The pressure will increase to a pressure of 2.6 atm

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1.5 moles of Al is how many<br> atoms?
aev [14]

Answer:

<h2>9.03 × 10²³ atoms </h2>

Explanation:

The number of atoms of Al can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 1.5 × 6.02 × 10²³

We have the final answer as

<h3>9.03 × 10²³ atoms</h3>

Hope this helps you

4 0
3 years ago
A sample of diborane gas (B2H6), a substance that bursts into flame when exposed to air, has a pressure of 345 torr at a tempera
Hitman42 [59]

Answer:

The final volume is 3.07L

Explanation:

The general gas law will be used:

P1V1 /T1 = P2V2 /T2

V2 =P1 V1 T2 / P2 T1

Give the variables to the standard unit:

P1 = 345 torr = 345 /760 atm = 0.4539atm

T1 = -15°C = -15 + 273 = 258K

V1 = 3.48L

T2 = 36°C = 36+ 273 = 309K

P2 = 468 torr = 468 * 1/ 760 atm = 0.6158atm

V2 = ?

Equate the values into the gas equation, you have:

V2 = 0.4539 * 3.48 * 309 / 0.6158 * 258

V2 = 488.0877 /158.8764

V2 = 3.07

The final volume is 3.07L

8 0
4 years ago
Balance this equation. If a coefficient of "1" is required, choose "blank" for that box. CO + O2 → CO2
liberstina [14]

Answer:

2co + o2 > 2co2

Explanation:

so that is tye answer

3 0
4 years ago
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What is the mass of the question?
musickatia [10]

Answer: I do not know

Explanation:

6 0
4 years ago
A sample of helium gas occupies a 10 cubic meter container at stp (273 k, 1 atm). what will the approximate volume become when t
Sloan [31]
He answer in here is b.7.5 cubic meters. We know this when we do the following calculation:
<span>(10 m^3) x (1 / 1.5) x ((32 + 273) / (273)) = 7.5 m^3 
</span>
5 0
3 years ago
Read 2 more answers
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