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Assoli18 [71]
3 years ago
6

A sample of the inhalation anesthetic gas Halothane, in a 500-mL cylinder has a pressure of 2.3 atm at 0°C. What will be the pre

ssure of the gas if its temperature is warmed to 37°C (body temperature)? (Hint: Which law will you apply if the volume is constant?)
Chemistry
2 answers:
STALIN [3.7K]3 years ago
8 0

Answer: 2.56atm

Explanation:

P1/T1=P2/T2

P1T2=P2T1

P2=P1T2/T1

P1=2.3atm

P2=?

T1=0+273=273k

T2=32+273=305k

P2=2.3*305/273

P2=701.5/273

P2=2.56atm

lilavasa [31]3 years ago
3 0

Answer:

The pressure will increase to a pressure of 2.6 atm

Explanation:

Step 1: Data given

Volume = 500 mL = 0.500L

Pressure = 2.3 atm

Temperature = 0°C = 273 K

Temperature is warmed to 37 °C = 310 K

Volume will stay constant

Step 2: Calculate the new pressure

p1/T1 = p2/T2

⇒with p1 = the initial pressure = 2.3 atm

⇒with T1 = the initial temperature = 0 °C = 273 K

⇒with p2 = the new pressure = TO BE DETERMINED

⇒with T2 = the new temperature = 37 °C = 310 K

2.3 atm / 273 K  = p2 / 310 K

p2 = 2.6 atm

The pressure will increase to a pressure of 2.6 atm

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