The molar concentration of Cl⁻ ions in a 1. 00 m solution of AgCl₂ with no excess silver ions is 0.020M.
<h3>How do we determine the molar concentration?</h3>
Molar concentration of Chloride ions present in the silver chloride solution will be calculated by using the formation constant equation as:
Kf = [AgCl₂] / [Ag²⁺][Cl⁻]²
For AgCl₂ value of Kf is 2.5×10⁵.
Chemical reaction with ICE table is:
Ag²⁺(aq) + 2Cl⁻(aq) → AgCl₂
Initial: 0 0 1
Change: +x +2x -x
Equilibrium: x 2x 1-x
On putting all the values on the Kf equation, we get
2.5×10⁵ = (1-x) / (x)(2x)²
x is negligible as compared to 1 so the term 1-x becomes 1,
2.5×10⁵ = 1 / 4x³
x = 9.97 × 10⁻³ M
Concentration of chloride ions = 2x = 2(9.97 × 10⁻³) = 0.020M.
Hence the molar concentration of chloride ions is 0.020M.
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Answer:
I can't draw diagrams on this web site but I can do with numbers I think. So an electron is moved from n = 1 to n = 5. I'm assuming I've interpreted the problem correctly; if not you will need to make a correction. I'm assuming that you know the electron in the n = 1 state is the ground state so the 4th exited state moves it to the n = 5 level.
n = 5 4th excited state
n = 4 3rd excited state
n = 3 2nd excited state
n = 2 1st excited state
n = 1 ground state
Here are the possible spectral lines.
n = 5 to 4, n = 5 to 3, n = 5 to 2, n = 5 to 1 or 4 lines.
n = 4 to 3, 4 to 2, 4 to 1 = 3 lines
n = 3 to 2, 3 to 1 = 2 lines
n = 2 to 1 = 1 line. Add 'em up. I get 10.
b. The Lyman series is from whatever to n = 1. Count the above that end in n = 1.
c.The E for any level is -21.8E-19 Joules/n^2
To find the E for any transition (delta E) take E for upper n and subtract from the E for the lower n and that gives you delta E for the transition.
So for n = 5 to n = 1, use -Efor 5 -(-Efor 1) = + something which I'll leave for you. You could convert that to wavelength in meters with delta E = hc/wavelength. You might want to try it for the Balmer series (n ending in n = 2). I think the red line is about 650 nm.
Explanation:
By solving 6x² - x - 2 = 0 through the quadratic equation we get the values of x are x = -1/2 , x = 2/3.
<h3>What is Quadratic equation ? </h3>
The polynomial equation of degree 2 in one variable is known as quadratic equation.
It is represented as
The given equation is 6x² - x - 2 = 0
Here,
a = 6
b = -1
c = -2
Put the values in above formula we get
Now separate the equation
x = 8/12 , x = -6/12
x = 2/3 , x = -1/2
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Note: The given question is incomplete on the portal. Here is the complete question.
Question: What is the answer of this equation 6x² - x - 2 = 0.
Answer: Both technicians are correct
Explanation: A chemical tester and exhaust gas analyzer are two important ways to check for gasket leakage