Answer:
80 ml
Explanation:
Moles to start = .04 L * .6 M/L = .024 moles
this is how much must be in the final dilution
.2 moles / liter * x liter = .024 moles
x = .024 / .2 = .12 liter final volume
start with . 040 then add .080 to get .12 liter
.080 liter = 80 ml
<span>after the 1940, the infention of : PASTEURIZATION permitted wines to be produced in places where climate was not ideal for wine production
after pasteurization process, all the microbes that exist within the wine are eliminated, which will prevent it from rottening. This make it possible to store wine for a long period of time even thought it's not in the harvesting climate</span>
Mole ratio:
MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl
2 moles KOH ---------------- 1 mole Mg(OH)₂
4 moles KOH ------------------- moles Mg(OH)₂
moles Mg(OH)₂ = 4 x 1 / 2
= 2 moles of Mg(OH)₂
molar mass Mg(OH)₂ = 58g/mol
mass of Mg(OH)₂ = n x mm
mass of Mg(OH)₂ = 58 x 2
= 116 g of <span> Mg(OH)₂</span>
hope this helps!