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uranmaximum [27]
3 years ago
7

I need help with these two

Chemistry
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

6. d,  7. a

Explanation:

6. Molarity is a number of moles solute in 1 L solution.

7. 1 L solution - 2.5 mol K2CO3

 20 L             - x mol K2CO3

x  =20*2.5/1 = 50 mol K2CO3

Molar mass(KCO3) = M(K) + M(C) + 3M(O)= 39 +12 +3*16= 99 g/mol

99 g/mol *50 mol = 4950 g KCO3 Closest answer is A.

Actually KCO3 does not exist, in reality it should be K2CO3.

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The volume of a gas is 4.0 L when the pressure is 1.00 atm. At the same temperature, what is the pressure at which the volume of
Leokris [45]

<u>Answer:</u> 2.00 atm

<u>Explanation:</u>

The gas is kept under the same temperature in this problem. Assuming the amount of gas is constant, we can apply the Boyle's law.

The Boyle's law equation,

P₁V₁ =  P₂V  ₂

Plug in the values,

1.00 atm x 4.0 L =  P₂  x 2.0 L

Simplify,

4.00 atm L = 2  P₂ L

Now flip the equation,

2  P₂ L = 4.00 atm L

Dividing both sides by 2 we get,

P₂ = 2.00 atm

8 0
3 years ago
When pure methanol is mixed with water the resulting solution feels warm would you expect this solution to be ideal?Explain
Pepsi [2]

Answer:

No

Explanation:

In ideal solutions, the interactions between solute - solvent are approximately the same as those of solute - solute and solvent - solvent, that is the interactions are to be practically indistintiguishable after disolution.

The moment we have a release of energy (the solution feels warm) we are to conclude that there are strong interactions between the water and methanol molecules so we would expect the solution to be non ideal.

The reason for the interactions is the presence of hydrogen bonds between methanol and water.

5 0
3 years ago
What is the empirical formula for a compound if a sample contains 3.72 g of P and 21.28 g of Cl
fenix001 [56]
M(P)=3.72 g
M(P)=31 g/mol

m(Cl)=21.28 g
M(Cl)=35.5 g/mol

n(P)=m(P)/M(P)
n(P)=3.72/31=0.12 mol

n(Cl)=m(Cl)/M(Cl)
n(Cl)=21.28/35.5=0.60 mol

P : Cl = 0.12 : 0.60 = 1 : 5

PCl₅ - is the empirical formula
6 0
3 years ago
If 6.02×1023 atoms of element Y have a mass of 28.09 g, what is the identity of Y?
Mazyrski [523]

Silicon is the element having a mass of 28.09 g

<u>Explanation</u>:

  • Silicon is the element having an atomic mass of 28.09 g / mol. So 28.09 g of silicon contains 6.023 \times 10^23 atoms. One mole of each element can produce one mole of compound.
  • The Atomic weight of an element can be determined by the number of protons and neutrons present in one atom of that element. So atomic weight expressed in grams always contain the same number of atoms( 6.023 \times10^23).
  • Avagadro number is the number of atoms of 1 mole of any gas at standard temperature and pressure. It has been determined that 6.023 \times 10^23 atoms of an element are equal to the average atomic mass of that element.
8 0
3 years ago
What are the products in a sodium and water reaction?
UkoKoshka [18]

Answer:

Sodium Hydroxide

Explanation:

7 0
3 years ago
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