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kumpel [21]
3 years ago
5

What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

$a$ and $b$ are integers?
Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0

YOU LITERIALLY ASKED THIS 7 TIMES ARE YOU OK?

is this still a problem you have?

if so ill solve it in one of the many other exact same threads.

You might be interested in
Which recursive formula can be used to generate the sequence below, where f(1) = 3 and n ≥ 1? 3, –6, 12, –24, 48, … f (n 1) = –3
Maslowich

The recursive formula will be equal to f(n + 1) = –2 f(n).

The complete question is given below:-

Which recursive formula can be used to generate the sequence below, where f(1) = 3 and n ≥ 1?

3, –6, 12, –24, 48, …

f (n + 1) = –3 f(n )

f (n + 1) = 3 f(n )

f (n + 1) = –2 f(n )

f (n + 1) = 2 f(n)

<h3>What is a function?</h3>

A function is defined as the expression that set up the relationship between the dependent variable and independent variable.

The recursive formula for this sequence is calculated as we will put the different values of n to find the values of the function in the series.

n  =  1

f(n) = 3

n = 2

f(2) = -2 (3) = -6

n = 3

f(3) = -2 (-6) = 12 and so on

Therefore the recursive formula will be equal to f(n + 1) = –2 f(n).

To know more about function follow

brainly.com/question/25638609

#SPJ1

8 0
2 years ago
Add and simplify 1/8 5/8
skelet666 [1.2K]
1+5=6 so 6/8 

Simplifying 6/8 is 3/4
8 0
4 years ago
Read 2 more answers
What adds to 17 but multiplies to 45
I am Lyosha [343]
No whole numbers do as if you look at the factors pairs of 45 none of them add to 17:

1, 45 = 46
3, 15 = 18
5, 9 = 14

The two numbers that add to 17 but multiply to 45 are can be calculated using the quadratic formula and are actually 13.72 and 3.28
7 0
4 years ago
How do you solve this?
liberstina [14]

Answer:

The answer is

<h2>{13}^{3}</h2>

Step-by-step explanation:

<h3>( {13})^{2}(  {13})^{ - 4} ( {13})^{5}</h3>

To solve the expression , use the rules of indices

Since the bases are the same and are multiplying we add the exponents

That's

<h3>{a}^{x}  \times  {a}^{y}  \times  {a}^{z}  =  {a}^{x + y + z}</h3>

So we have

<h3>( {13})^{2}(  {13})^{ - 4} ( {13})^{5}   =  {13}^{2 - 4 + 5}  \\  =  {13}^{ - 2 + 5}</h3>

We have the final answer as

<h3>{13}^{3}</h3>

Hope this helps you

3 0
4 years ago
Car = V-8 sedan
jenyasd209 [6]

Answer:

$500

Step-by-step explanatioThe numberber of years driven is the first and second year

= 2

Miles driven

First year= 15,500

Second year= 14,500

Therefore the cost of depreciation can be calculated as follows

15,500-14,500/2

= 1000/2

= 500

Hence the cost of depreciation is $500

3 0
3 years ago
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