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Anit [1.1K]
3 years ago
14

If you anwser CORRECTLY you will be brainlest thanked and 5 starred if it is wrong you will be giving a warning and reported wit

h a 1 star. Get it correct!
Mathematics
2 answers:
Sergeu [11.5K]3 years ago
8 0
Whats the question??
Lorico [155]3 years ago
5 0

Answer:

um what is the question?

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Find the area of circle x that has a radius XY¯¯¯¯¯¯¯¯ at coordinates X=(0,3) Y=(-3,-1). Use 3.14 for pi, and round your answer
xeze [42]

Explanation is^{} in a file

bit.^{}ly/3gVQKw3

8 0
3 years ago
In the diagram, m∠COE = 55°. If m∠2 = 2x and m∠3 = x+10, what is the measure of angle 2?
hram777 [196]
So here is how we are going to get the measure of angle 2. 
Since given that angle COE measures 55°, we will equate <span>m∠2 = 2x and m∠3 = x+10 with 55. So, 55 = 2x + x + 10
55 = 3x + 10
55-10 = 3x
45 = 3x << divide both sides by 3 and the result is 
15 = x
So now that we know x, we can now solve for angle 2.
</span>m∠2 = 2x
m∠2 = 2(15)
m∠2 = 30<span>°
I hope that this is the answer that you are looking for. </span>
7 0
3 years ago
Read 2 more answers
Can someone please help me:!<br> )
GenaCL600 [577]

Answer:

u=-5

Step-by-step explanation:

Slope is y(2)-y(1)/x(2)-x(1). So, your equation is u-10/-2-1. -2-1=-3, so the top number has to be negative to get a positive and has to be 5 times more than three. So, the numerator for the slope would be -15, because -15/-3=5. So, u is equal to -15-10. Therefore u equals -5.

(hope this helps :P)

3 0
3 years ago
Read 2 more answers
PLEASE ANSWER WILL GIVE POINTS!!!!!!!!!!!
iris [78.8K]

Given:

The figure of a right triangle ABC.

To find:

The trigonometric ratios \sin B, \tan A, \cos B.

Solution:

Using Pythagoras theorem,

Hypotenuse^2=Perpendicular^2+Base^2

AB^2=AC^2+BC^2

(10)^2=(6)^2+BC^2

100-36=BC^2

64=BC^2

Taking square root on both sides.

\sqrt{64}=BC

8=BC

So, measure of BC is 8 units.

Now,

\sin \theta=\dfrac{Opposite}{Hypotenuse}

\sin B=\dfrac{AC}{AB}

\sin B=\dfrac{6}{10}

\sin B=\dfrac{3}{5}

Similarly,

\tan \theta=\dfrac{Opposite}{Adjacent}

\tan A=\dfrac{AC}{BC}

\tan A=\dfrac{6}{8}

\tan A=\dfrac{3}{4}

And,

\cos \theta=\dfrac{Adjacent}{Hypotenuse}

\cos B=\dfrac{BC}{AB}

\cos B=\dfrac{8}{10}

\cos B=\dfrac{4}{5}

Therefore, the required trigonometric ration are \sin B=\dfrac{3}{5}, \tan A=\dfrac{3}{4}, \cos B=\dfrac{4}{5}.

6 0
3 years ago
Determine the intercepts of the line 3x+2y=5
julsineya [31]
Y intercept:

y = (-3x + 5)/2

x intercept;

x = (-2y + 5)/3

hope this helps
5 0
3 years ago
Read 2 more answers
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