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Vinil7 [7]
3 years ago
11

HELP ASAP!!! IM BEING TIMED. Use synthetic division to test one potential root. Enter the numbers that complete the division pro

blem.

Mathematics
2 answers:
PtichkaEL [24]3 years ago
8 0

Step-by-step explanation:

1 * (-5) = -5     a = -5

6 + (-5) = 1      b = 1

1 * (-5 ) = -5     c = -5

-7 + -5 = -12     d = -12

Keith_Richards [23]3 years ago
5 0

Answer:

So a=-5,c=-5,b=1,c=-12

Step-by-step explanation:

In synthetic division, you add the columns inside the box, you multiply the number under the bar by the number outside to get the next number in the column.

Example

Divide x^3+10x^2-5x+1 by x+4.

-4 goes on the outside because  you are dividing by (x+4).

-4   |    1          10        -5        1

     |               -4       -24        116

     -------------------------------------

          1           6        -29        117

So your problem you have this setup:

-5  |   1       6           -7         -60

    |

     ---------------------------------------

This is enough information to figure out the letter's you have:

So your problem you have this setup:

-5  |   1       6           -7         -60

    |          -5          -5           60

     ---------------------------------------

        1         1         -12          0

So a=-5,c=-5,b=1,c=-12

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2 years ago
Solve by the elimination method. Check your work.
sweet-ann [11.9K]

Answer:

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Step-by-step explanation:

To check your work plug the numbers back into one of the equations and see if it's true.

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1. I distributed 3 to all the numbers so that 9y and -9y would cancel then you add like terms.

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3 years ago
Let X be a normal random variable with mean 3 and variance 4. (a) Find the probability P(2 < X < 6). (b) Find the value c
Vanyuwa [196]

Answer:

a) the probability of (2 < X < 6) is 0.6247

b) the value of c is 3.878

c) the value of E[ x² ] is 13

Step-by-step explanation:

Given that;

mean μ = 3

variance = 4

standard deviation s = √variance  = √4 = 2

(a) Find the probability P(2 < X < 6)

P(2 < X < 6) = p( (x - μ / s ) < z <  (x - μ / s ) )

= p( (2 - 3 / 2 ) < z < (6 - 3 / 2 ) )

= p( -0.5  < z <  1.5)

from z-score table, 1.5; z = 0.9332 and -0.5; z = 0.3085

so

P(2 < X < 6)  = 0.9332 - 0.3085 = 0.6247

Therefore, the probability of (2 < X < 6) is 0.6247

b) Find the value c such that P(X > c) = 0.33

with p-value = 0.33, the corresponding z -score to the right is 0.439

we know that;

z = x - μ / s

we substitute

0.439 = x - 3 / 2

x - 3 = 2 × 0.439

x - 3 = 0.878

x = 0.878 + 3

x = 3.878

Therefore, the value of c is 3.878

c) Find E[ x² ].

Variance = E[ x² ] - [ mean ]²

E[ x² ]  = Variance + [ mean ]²

we substitute

E[ x² ]  = 4 + [ 3 ]²

E[ x² ]  = 4 + 9

E[ x² ]  = 13

Therefore, the value of E[ x² ] is 13

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The problem given above can be solved through the concept of permutation because of the importance of the arrangements. This may be solved through calculators directly by keying in,
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That is, the permutation of 10 taken 5. The answer to this permutation is 30,240. 
3 0
3 years ago
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