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Ludmilka [50]
2 years ago
8

Johnny scored an 82 on his review quiz and a 94 on his actual test 1. Use an absolute and relative change to compare his actual

test score to his review score. Complete the sentences below by copying each filling in the correct value. Make sure to use "more" or "less" in your sentence.
• What is the absolute change?
The review quiz is ______________________________ than the actual test.
The actual test is ______________________________ than the review quiz.
• What is the relative change?
The review quiz is ______________________________ than the actual test.
The actual test is ______________________________ than the review quiz.
• Why are the values different in part 2?
Mathematics
1 answer:
Nostrana [21]2 years ago
7 0

Answer:

i dont know

Step-by-step explanation:

sorry

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In the diagram below. C is an equal distance to A and B.
Fynjy0 [20]

Answer:

C(50;-20)

Step-by-step explanation:

The question is asking for the midpoint of the line.

The triangle is formed by placing a line directly from the y-axis to the x-axis.

The midpoint theorem is[ (x1+x2)/2 ; (y1+y2)/2 ].

your coordinates at A is (0;-40), because the x value is 0 on the line as shown in the diagram above point A.

Your coordinates for B are (100;0)

C[(x1+x2)/2 ; (y1+y2)/2 ]

C [(0+100)/2 ; (-40+0)/2 ]

C[ 100/2 ; -40/2]

C (50 ; -20)

7 0
2 years ago
A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time
user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

a(t) = 24t + 2

Velocity:

v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

v(t) = 12t^{2} + 2t + 13

Position:

s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K

Since s(0) = 3

s(t) = 4t^{3} + t^{2} + 13t + 3

What is its position at time t=5?

This is s(5).

s(t) = 4t^{3} + t^{2} + 13t + 3

s(5) = 4*5^{3} + 5^{2} + 13*5 + 3

s(5) = 593

It's position at time t = 5 is 593.

3 0
3 years ago
A bag contains 5 red marbles, 8 blue marbles and 6 green marbles. If three marbles are drawn out of the bag, what is the probabi
Gala2k [10]

70000000000 + 8818282828828

8 0
3 years ago
For exercises 33-36 find each sum or difference 1 2/5+1 1/3
ololo11 [35]

Answer:

41/15

Step-by-step explanation:

7 0
3 years ago
The expected activity time in PERT analysis is calculated as: the weighted average of a, m, and b, with m weighted 4 times as he
maria [59]

Answer:

\text{the weighted average of a, m, and b, with m weighted 4 times as heavily as a and b.}

Step-by-step explanation:

\text{The expected activity time in PERT analysis is calculated as:}

\mathbf{\dfrac{a+4m + b}{6}}

where;

\text{a = optimistic duration; }

\text{m = most likely duration and;}

\text{ b = pessimistic duration     from the above formula.}

3 0
2 years ago
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