Answer:
The sign would be 784 ft. long.
Step-by-step explanation:
The sign would be painted across the total perimeter of the building.
- the distance across the front of the store is 294 feet
- the distance from the front to the back is one third of this distance = (1/3) × 294 = 98 ft.
The perimeter of a rectangular = 2(L + B)
L = length of the building = 294 ft.
B = Breadth of the building = 98 ft.
Perimeter of the chocolate factory that the Sign would be painted across = 2(294 + 98) = 784 ft.
Hope this Helps!!!
The correct answer is 0.48 because as you can tell the probability of it landing on heads is just a little bit below the probability of getting tails. Hope I helped!
Answer:
<h2>
3/5</h2>
Step-by-step explanation:
If Jennifer has 25 books on her bookshelf and she has 10 fiction books, the number of non-fiction books she has will be 25-10 = 15 non- fiction books.
Probability is the likelihood or chance that an event will occur.
Probability = Expected outcome of event/total outcome.
Since we want the expression that represents the probability that the book she selects will be a non-fiction book, our expected outcome will be 15(the total non fiction she selected)
The total outcome will be the total number of books i.e 25.
Probability that she elects non fiction book = 15/25
= 3/5
It seems most likely that ...
... Samantha will save $37.50 because she must first find the 25% sale price before taking the extra 50% reduction
_____
In the real world, it seems probable that Samantha will be offered the choice of using the coupon <em>or</em> the sale discount. If she chooses tht 50% coupon, her savings will be $30. If she chooses the marked sale discount, her savings will be $15.
The scenario above assumes she gets 50% off the sale price of $45, so saves $15+22.50 = $37.50 off the original price.
Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval
The degrees of freedom is
df = n-1 = 19
We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.
The 99% confidence interval is
xbar +/- t*(s/√n)
t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)
Answer: The 99% confidence interval is (15.07, 19.93)
