The population of Farmersville can be modeled by the inequality y > 2,000x + 2,100, where x is the number of years since 2010
1 answer:
Answer:
The population can be greater than 6,100 but less than 6,300, and thus, we cannot determine if the population of Farmersville will be greater than 6,300 in 2012.
Step-by-step explanation:
Inequality for the population of Farmsville:
The inequality for the population of Farmsville in x years after 2010 is given by:
Will the population of Farmersville be greater than 6,300 in 2012?
2012 is 2012-2010 = 2 years after 2010, so we have to find y(2).
The population can be greater than 6,100 but less than 6,300, and thus, we cannot determine if the population of Farmersville will be greater than 6,300 in 2012.
You might be interested in
Answer:
10.36
Step-by-step explanation:
So your solution would be:
Just try to remember PEMDAS.
Parenthesis, Exponent, Multiplication/Division, Addition/Subtraction.
This is the order we follow when going about expressions with many operations.
Let's start with the parenthesis part. Notice that there is an exponent beside the parenthesis enclosing the fraction. Here we use the quotient to a power rule. We distribute the exponent to the numerator and the denominator.
Now that we got the parenthesis and exponent out of the way, let's move on to the next. Multiplication/Division. Whichever comes first, you do it first.
We have a fraction so we do that first. Then we do the multiplication after.
Next we do the addition/subtraction. Again, whichever comes first.