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2 years ago

Ahh help!!

Mathematics

1 answer:

Rzqust [24]2 years ago

3 0

Answer:

I think its 678.24

Hope it helps!

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What is the answer to 10=4a

Archy [21]

Answer:

5/2

Step-by-step explanation:

divide both sides by 4

3 0

3 years ago

A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at

valina [46]

Answer:

$P(Same)=\frac{61}{190}$

Step-by-step explanation:

Given

$Red = 5$

$White = 6$

$Black = 9$

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

$Total = 5 + 6 + 9$

$Total = 20$

This is calculated as:

$P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)$

So, we have:

$P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1} + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

$P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1} + \frac{9}{20} * \frac{9- 1}{20- 1}$

$P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19} + \frac{9}{20} * \frac{8}{19}$

$P(Same)=\frac{20}{380} + \frac{30}{380} + \frac{72}{380}$

$P(Same)=\frac{20+30+72}{380}$

$P(Same)=\frac{122}{380}$

$P(Same)=\frac{61}{190}$

4 0

2 years ago

Fill in the missing values in the formula. What is the variance? 0 3.217 3.522 12.405 148.86

Lerok [7]

Answer: This’s the answer for your question 12.405

6 0

3 years ago

The pressure applied to a leverage bar varies inversely as the distance from the object. If 150 pounds is required for a distanc

AlexFokin [52]

Answer:

500 pounds

Step-by-step explanation:

Let the pressure applied to the leverage bar be represented by p

Let the distance from the object be represented by d.

The pressure applied to a leverage bar varies inversely as the distance from the object.

Written mathematically, we have:

$p \propto \dfrac{1}{d}$

Introducing the constant of proportionality

$p = \dfrac{k}{d}$

If 150 pounds is required for a distance of 10 inches from the object

p=150 pounds
d=10 inches

$150 = \dfrac{k}{10}\\\\k=1500$

Therefore, the relationship between p and d is:

$p = \dfrac{1500}{d}$

When d=3 Inches

$p = \dfrac{1500}{3}\\\implies p=500$ pounds$

The pressure applied when the distance is 3 inches is 500 pounds.

4 0

3 years ago

What is the area of this figure? Enter your answer in the box.

Paladinen [302]

The area would be 35 cm squared.

Lets break it down:
Triangle- The area of a triangle is base×height÷2
so if we plug in the numbers, the base would be 5 (the length) and the height would be 4 (the height). 5×4= 20÷2= 10.
Square- The area of a square is base×height so if we pluged in the numbers, the base is 5 (the length) and the height is 5 (the height). 5×5= 25.

10+25= 35 cm squared

Hope this helps!

6 0

3 years ago