Can someone please help me ASAP
1 answer:
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Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
+6=perimeter
Hope that helps :)
If f(x) = (6x-11), then f(-6) = -47.
We are provided in the question statement with a function "f(x)" whose output is a polynomial of 1 variable and degree 1.
To obtain the value of f(-6) from the output polynomial of the function f(x), we will simply need to substitute (-6) as the value of x in the polynomial and calculate the final value.
So,
Hence, f(-6) = -47.
- Polynomial: In mathematics, an expression of more than two algebraic terms, especially the sum of several terms that contain the same variable(s) of different powers and individual, distinct co-efficients.
- Function: In Mathematics, a function is an operator which on taking input, provides a certain output.
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