All categories

2 years ago

Find the sum of the first 10 terms of the following sequence 4, -16, 64

Mathematics

1 answer:

guajiro [1.7K]2 years ago

6 0

Answer:

838860

Step-by-step explanation:

How do you find the sum of the first 10 terms?

To sum up the terms of this arithmetic sequence: a + (a+d) + (a+2d) + (a+3d) +

Example: Add up the first 10 terms of the arithmetic sequence:

a = 1 (the first term)

d = 3 (the "common difference" between terms)

n = 10 (how many terms to add up)

What is the sum of the first 10?

The number series 1, 2, 3, 4 , 9, 10. Therefore, 55 is the sum of positive integers upto 10.

You might be interested in

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Vesnalui [34]

Since they are independent events to find the probability of both is P(A) * P(B)

P(A) = P(Heads) = $\frac{1}{2}$
P(B) = P(Roll ≥ 4) = $\frac{3}{6} = \frac{1}{2}$

Now multiply those fractions together

$\frac{1}{2} * \frac{1}{2} = \frac{1}{4}$ = P(Heads & ≥ 4)

5 0

3 years ago

Find the sine ratio of angle Θ.

charle [14.2K]

Answer:

sometimes

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Write a problem that could be modeled with y=200(0.9).

Lunna [17]

First, I need to decide what equation this is like.

I believe this is y=mx.

We know that x is typically the input, and m is the constant function.

Y is the output.

So the original function may have been y=200x.

The only difference is now we've been given something to apply to the equation, in place of x.

2. Imagine a cloning machine. Whatever you put in, you get a copy of, and the original thing you put in. Its function would be y=2x. Let's pretend we decided to put three things in; 3 would go where x is.

Y would be the result of 3 copies and their originals, or 2(3).

(6=2(3))

Now, when someone else decides to use the cloning machine, they may put any number in, but the only properties that will change are y and x, not m.

The function will remain y = 2x. Any number could go in place of x, and multiplying x by 2 will give you the y. As long as you have a different value for x, the y will never be the same.

3. So now we have an understanding of what it means, we see that we have been given an x value to insert; an input.

A more practical example could be someting with money. This won't be entirely realistic, because we are dealing with a fraction of a number and another large number.

4. I decided to go with flour. I wanted the 200 to represent pennies, or cents. Before I landed on this, I looked up the cost of flour per pound. I found that the average is .43 dollars, which isn't terribly close to two dollars. But maybe the flour is high quality, so we can stick with that.

5. Seeing that this equation, y=200x, means we are charging 200 cents, or two dollars, we can write a problem from here.

Sylvia is in charge of selling home-harvested flour from an organic farm. She charges two dollars per pound of flower. Today, her next-door neighbors hope to buy a ninth of pound of flour, and they insist on paying with pennies. How many pennies do they need to pay for their order?

Let me know if this helped, or if you have any questions!

3 0

3 years ago

In a population of 10,000, there are 5000 nonsmokers, 2500 smokers of one pack or less per day, and 2500 smokers of more than on

Kazeer [188]

Answer:

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

Step-by-step explanation:

We have to write the transition matrix M for the population.

We have three states (nonsmokers, smokers of one pack and smokers of more than one pack), so we will have a 3x3 transition matrix.

We can write the transition matrix, in which the rows are the actual state and the columns are the future state.

- There is an 8% probability that a nonsmoker will begin smoking a pack or less per day, and a 2% probability that a nonsmoker will begin smoking more than a pack per day. Then, the probability of staying in the same state is 90%.

- For smokers who smoke a pack or less per day, there is a 10% probability of quitting and a 10% probability of increasing to more than a pack per day. Then, the probability of staying in the same state is 80%.

- For smokers who smoke more than a pack per day, there is an 8% probability of quitting and a 10% probability of dropping to a pack or less per day. Then, the probability of staying in the same state is 82%.

The transition matrix becomes:

$\begin{vmatrix} &NS&P1&PM\\NS& 0.90&0.08&0.02 \\ P1&0.10&0.80 &0.10 \\ PM& 0.08 &0.10&0.82 \end{vmatrix}$

The actual state matrix is

$\left[\begin{array}{ccc}5,000&2,500&2,500\end{array}\right]$

We can calculate the next month state by multupling the actual state matrix and the transition matrix:

$\left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4950&2650&2400\end{array}\right]$

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

To calculate the the state for the second month, we us the state of the first of the month and multiply it one time by the transition matrix:

$\left[\begin{array}{ccc}4950&2650&2400\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4912&2756&2332\end{array}\right]$

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

If we repeat this multiplication 12 times from the actual state (or 10 times from the two-months state), we will get the state a year from now:

$\left( \left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] \right)^{12} =\left[\begin{array}{ccc}4792.63&3005.44&2201.93\end{array}\right]$

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

3 0

3 years ago

PLS HELP! solve by completing the square x²+4x=8

masya89 [10]

Step-by-step explanation:

x²+4x=8

rearrange

x² + 4x - 8 = 0

half of 4 is 2

x² + 4x + 2² - 2² - 8 = 0

do x² + 4x + 2²

multiplies to give 4 adds to give 4

2+ 2

(x + 2)²

(x + 2)² - 2² - 8

(x + 2)² - 4 - 8

(x + 2)² - 12

(x + 2 + √12) (x + 2 - √12)

√12 = √4 * √3 = 2 √3

(x + 2 + 2√3) (x + 2 - 2√3)

4 0

2 years ago

Find the sum of the first 10 terms of the following sequence 4, -16, 64​

Find the sum of the first 10 terms of the following sequence 4, -16, 64