The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.
So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.
f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
Find <span>tan<span>(<span><span>5π</span>12</span>)</span></span> and sin ((5pi)/12)
Answer: <span>±<span>(2±<span>√3</span>)</span>and±<span><span>√<span>2+<span>√3</span></span></span>2</span></span>
Explanation:
Call tan ((5pi/12) = t.
Use trig identity: <span><span>tan2</span>a=<span><span>2<span>tana</span></span><span>1−<span><span>tan2</span>a</span></span></span></span>
<span><span>tan<span>(<span><span>10π</span>12</span>)</span></span>=<span>tan<span>(<span><span>5π</span>6</span>)</span></span>=−<span>1<span>√3</span></span>=<span><span>2t</span><span>1−<span>t2</span></span></span></span>
<span><span>t2</span>−2<span>√3</span>t−1=0</span>
<span>D=<span>d2</span>=<span>b2</span>−4ac=12+4=16</span>--> <span>d=±4</span>
<span>t=<span>tan<span>(<span><span>5π</span>12</span>)</span></span>=<span><span>2<span>√3</span></span>2</span>±<span>42</span>=2±<span>√3</span></span>
Call <span><span>sin<span>(<span><span>5π</span>12</span>)</span></span>=<span>siny</span></span>
Use trig identity: <span><span>cos2</span>a=1−2<span><span>sin2</span>a</span></span>
<span><span>cos<span>(<span><span>10π</span>12</span>)</span></span>=<span>cos<span>(<span><span>5π</span>6</span>)</span></span>=<span><span>−<span>√3</span></span>2</span>=1−2<span><span>sin2</span>y</span></span>
<span><span><span>sin2</span>y</span>=<span><span>2+<span>√3</span></span>4</span></span>
<span><span>siny</span>=<span>sin<span>(<span><span>5π</span>12</span>)</span></span>=±<span><span><span>√<span>2+<span>√3</span></span></span>2</span></span></span>
Answer:
irrational
Step-by-step explanation:
because an irrational number goes on forever so no matter what number is added to it it will always be irrational.
Subtract 3 from both sides,
Let x = X and y - 3 = Y
Then,
So, we have shifted the origin to a point (0, 3).
This is an odd function and the graph of an odd function is symmetrical about the origin.
That is, symmetrical about X = 0, Y = 0
Symmetrical about x = 0,, y - 3 = 0
Symmetrical about x = 0, y = 3.
Hence, the graph is symmetrical about the point (0, 3).
Answer:
The two iterations of f(x) = 1.5598
Step-by-step explanation:
If we apply Newton's iterations method, we get a new guess of a zero of a function, f(x), xₙ₊₁, using a previous guess of, xₙ.
xₙ₊₁ = xₙ - f(xₙ) / f'(xₙ)
Given;
f(xₙ) = cos x, then f'(xₙ) = - sin x
cos x / - sin x = -cot x
substitute in "-cot x" into the equation
xₙ₊₁ = xₙ - (- cot x)
xₙ₊₁ = xₙ + cot x
x₁ = 0.7
first iteration
x₂ = 0.7 + cot (0.7)
x₂ = 0.7 + 1.18724
x₂ = 1.88724
second iteration
x₃ = 1.88724 + cot (1.88724)
x₃ = 1.88724 - 0.32744
x₃ = 1.5598
To four decimal places = 1.5598
