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Tema [17]
3 years ago
11

Please help mememememmeemmemeem

Mathematics
2 answers:
sladkih [1.3K]3 years ago
7 0
I this the answer is A
ololo11 [35]3 years ago
7 0
Answer:

A

Explanation:

You can get this by carefully looking at the graphs to see which ones fit the problem above.
Or, if you’re still unsure about the answer, you can fill in the graph above as well. It would just be more time consuming if you were gonna do that.
If you did all of that, you’d find out that “A” would be precise and correct.
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4 years ago
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What is the mean of the number 48,78,54,68
lorasvet [3.4K]

Answer:

62

Step-by-step explanation:

mean =  \frac{48 + 78 + 54 + 68}{4}  \\  =  \frac{248}{4}   \\  = 62

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3 years ago
5000 at 9% for 4 years. pls help me <br>​
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Answer:

$5,024

Step-by-step explanation:

8 0
3 years ago
Kayla buys a video game for $19 plus a 6% tax. Michael buys a volleyball for $18 plus a 6% tax. Enter the difference in the amou
adelina 88 [10]

Answer:

Kayla = $20.14

Michael = $19.08

The Difference = 1.06

Step-by-step explanation:

<em><u>How to solve.</u></em>

First, you need to add up how much Kayla is paying for the video game, plus the 6% tax.

19.00 + 6% = 20.14

Then, you need to do the same with Michael's.

18.00 + 6% = 19.00

To find the difference between how much Kayla and Michael paid for their items, you need to subtract their total.

20.14 - 19.00 = 1.06

and the nearest cent would be 1.10.

<u><em>I hope this helped</em></u>.<em><u>!</u></em>

6 0
3 years ago
Which equation is a direct variation function? y = x y = 1/4 x + 2 y = x2 , y = 4,
Soloha48 [4]

Answer:

y=x and y=\frac{1}{4}x

Step-by-step explanation:

We know,

'Direct Variation function' is the function where two quantities vary directly i.e. variables x and y are said to be directly varying if 'y=kx' where k is the constant of variation.

Thus, from the options, we see that the function,

y=x is varying directly with the constant of variation i.e. k = 1.

y=\frac{1}{4}x is also varying directly with constant k=\frac{1}{4}

5 0
3 years ago
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