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Evgen [1.6K]
3 years ago
13

I need help with these questions (see image). Please show workings.​

Mathematics
2 answers:
Anton [14]3 years ago
5 0

Answer:

  • 24 cm

Step-by-step explanation:

The  chord, if the ends connected with the center, form an isosceles triangle with two sides being a radius of the circle.

<u>We have:</u>

  • Length of chord = x
  • Height of triangle = h = 5 cm
  • Radius = r = 26/2 = 13 cm

<u>From the triangle we get:</u>

  • (x/2)² + h² = r²
  • x²/4 + 5² = 13²
  • x²/4 = 144
  • x/2 = 12
  • x = 24

The length of the chord is 24 cm

denpristay [2]3 years ago
4 0

Answer:

24 cm

Step-by-step explanation:

The altitude from the centre to the chord is 5 cm and bisects the chord.

The radius of the circle is 26 cm ÷ 2 = 13 cm

There is a right triangle formed with legs 5 and x ( x is half the chord )

The hypotenuse is the radius, then using Pythagoras' identity

x² + 5² = 13²

x² + 25 = 169 ( subtract 25 from both sides )

x² = 144 ( take the square root of both sides )

x = \sqrt{144} = 12

Then

length of chord = 2x = 2 × 12 = 24 cm

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The lengths of a triangle are 12 and 23 meters find the range of possible lengths for the third side
sergij07 [2.7K]

Answer: 11 < x < 35

suppose: the length of the third side is x

because x is the third side of a triangle

=> 23 - 12 < x < 23 + 12

⇔ 11 < x < 35

Step-by-step explanation:

6 0
2 years ago
The perimeter of rectangle living room is 40 m the living room is 10 m wide what is the length of the living room
Yuri [45]

Answer:

Width of the room = 5 meters

Step-by-step explanation:

the rectangular living room is calculated as length * width

The area is given to be equal to 40 sq. meters (area = 40 sq. meters)

Let the width = x meters

Length = X+3 meters

Area = Length * Width

40 = X * (X+3)

40 = X^2 + 3X

We solve this quadratic equation

So x = 5 or x= -8

Width  cannot be negative, so we reject x =-8

So x = 5 is the answer

8 0
2 years ago
5h+6y+4h+9y=3h+5y6h+9y
Leokris [45]
H=6y/5y^(6) -6

hope this helps!!!!!!!!
3 0
3 years ago
According to Masterfoods, the company that manufactures M&amp;M's, 12% of peanut M&amp;M's are brown, 15% are yellow, 12% are re
Luda [366]

Answer:

The questions asked are

If you randomly select 4 peanuts

1. Compute the probability that exactly three of the four M&M’s are brown

2. Compute the probability that two or three of the four M&M’s are brown.

3. Compute the probability that at most three of the four M&M’s are brown.

4. Compute the probability that at least three of the four M&M’s are brown.

Step-by-step explanation:

Given the following information

Brown=12%. P(B)=0.12

Yellow=15%. P(Y)=0.15

Red=12%. P(R), =0.12

Blue=23%. P(B) =0.23

Orange, =23%. P(O) =0.23

Green=15%. P(G)=0.15

Question 1.

They are independent events

If there are exactly three brown and the last is not brown

P(B n B n B n B')

P(B)×P(B)×P(B)×P(B')

0.12×0.12×0.12×(1-P(B))

0.001728×(1-0.12)

0.001728×0.88

0.00152.

0.152%

2. If two or three are brown

I.e we are going to two brown and two none brown or three brown and one not brown. (P(B)×P(B)×P(B')×P(B'))+ (P(B)×P(B)×P(B'))

(0.12×0.12×0.88×0.88)+(0.12×0.12×0.12×0.88)

0.0112+0.00152

0.0127

1.27%

3. At most three brown out of four then we are going to have

BBBB', BBB'B', BB'B'B', B'B'B'B'

These are the cases of at most three brown.

P(B)×P(B)×P(B)×P(B') + P(B)×P(B)×P(B')×P(B') + P(B)×P(B')×P(B')×PB')+ P(B')×P(B')×P(B')×P(B')=

0.12×0.12×0.12×0.88+ 0.12×0.12×0.88×0.88+ 0.12×0.88×0.88×0.88+ 0.88×0.88×0.88×0.88=0.694

0.694

69.4%

4. At least 3 brown out of four selection

I.e BBBB', BBBB

These are the two options

P(B)×P(B)×P(B)×P(B') + P(B)×P(B)×P(B)×P(B)=

0.12×0.12×0.12×0.88 + 0.12×0.12×0.12×0.12

0.001728

0.173%

4 0
2 years ago
Read 2 more answers
Please help top and bottom.
Helga [31]
1. Perimeter
22a + 2(6a + 8) -4 = p

[I got 22a from 12a + 10a]

2. If p = 250, what is a?

22a + 2(6a + 8) - 4 = 250
Distributive property
22a + 12a + 16 - 4 = 250
Add like terms
34a + 12 = 250
Subtract 12 by both sides
34a = 238
Divide 34 by both sides
a = 7
3 0
2 years ago
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