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Misha Larkins [42]
3 years ago
12

What is the solution to the system of equations? y = 2x -1 y = -x +5

Mathematics
2 answers:
PolarNik [594]3 years ago
8 0

x= −2 and y=3

I can't explain this very well, sorry.

Anna71 [15]3 years ago
6 0
The solution is:

x= 4/3

y= 11/3.

Step by step: (substitution)



2x+1=-x+5

Add x to both sides.


3x+1=5.

Subtract 1.

3x=4.

Divide by 3.


x=4/3.

Use 4/3 instead of x to find y.

y=-(4/3)+5

y= 11/3.

Hope this helped!! :)
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Solve the inequality 1.6-(3-2y)<5.

1. Rewrite this inequality without brackets:

1.6-3+2y<5.

2. Separate terms with y and without y in different sides of inequality:

2y<5-1.6+3,

2y<6.4.

3. Divide this inequality by 2:

y<3.2

4. The greatest integer that satisfies this inequality is 3.

Answer: 3.

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3 years ago
The choir is selling candy bars to raise money for a trip they sell each candy bar for $5 there are 7 candy bars in each box and
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Step-by-step explanation: Lets first figure out how much money a box of candy bars is worth. We know that each candy bar is worth $5 and that there are 7 candy bars per box. We can multiply 7*5 to figure out that each box is worth $35.

Now lets figure out how many boxes can be sold each day. Each student can sell two boxes a day. 5 students selling 2 boxes each is 5*2= 10 boxes total sold a day.

Now finally we use what we found to figure out the amount of money made per day. We know that there are 10 boxes being sold and that each box makes them $35. We just multiply 10 boxes by $35 to get $350 dollars each day.

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3 years ago
Two adjacent angles form a complementary relationship. One angle is twelve more than twice the other angle. Draw a picture to re
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Answer:

The angles are 26 and 64

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When two angles are complementary, what this means is that the add up to 90 degrees

Now, let’s say one of the angles is x, the other angle is 12 more than twice it; mathematically that would be 2x + 12

Since they add up to be 90, we have

x + 2x + 12 = 90

3x + 12 = 90

3x = 90-12

3x = 78

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A: $150

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So Company C has the best rate.

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