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Lina20 [59]
2 years ago
6

Which combination of factors is most likely to produce a significant value for an independent-measures t statistic?.

Mathematics
1 answer:
SashulF [63]2 years ago
8 0

Answer: A large mean difference and small sample variances ​

Step-by-step explanation:

<em>Effect size (η)</em> is a statistical measure that determines the strength of the association (numerically) between two variables.  For example, if we have data on the weight of male and female candidates and we realize that, on average, males are heavier than females, the difference between the weight of males and the weight of female candidates is known as the effect size.

The larger the effect size, the larger the weight difference between males and females will be.  

Statistic effect size helps us in analyzing if the difference is factual or if it is affected by a change of factors.  

In hypothesis testing, effect size, power, sample size, and critical significance level are related to each other.

The effect size formula for a hypothesis test of mean difference is:

<em>η = </em>\frac{x1-x2}{\sqrt[]{8^2} }

The denominator s² is the combined sample variance.

8^2 = ⊕

The effect size is affected by two components:

Sample mean difference

Sample variance.

As the sample mean difference is directly proportional to the effect size, on increasing the sample mean difference value the effect size will also increase.

Ans the sample variance is inversely proportional to the the effect size, on decreasing the sample variance value the effect size will increase and vice-versa.

Thus, the correct option is A large mean difference and small sample variances

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In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t
Nesterboy [21]

Answer:

a) 0.06

b) 0.778

Step-by-step explanation:

Let's suppose a community of 100 families just to facilitate the calculation.

30% of the families own a dog

Dog = 30% of 100 = 30

20% of the families that own a dog also own a cat = 20% of 30 = 6

27% of all the families own a cat = 27% of 100 = 27

So, 6 families own a dog and a cat.

As 30 families own a dog, [30 - 6 =] 24 families own only dogs

As 27 families own a cat, [27 - 6 = ] 21 families own only cats

See picture attached.

a) What is the probability that a randomly selected family owns both a dog and a cat?

P(dog and cat) = dog ∩ cat/total = 6/100 = 0.06

b) What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

So, only cat/total cat

P (not dog|cat) = 21/27 = 0.778

3 0
3 years ago
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Salsk061 [2.6K]

Answer:

f>2  or f<-2

Step-by-step explanation:

f^2−9>−5

Add 9 to each side

f^2−9+9>−5+9

f^2 >4

Take the square root of each side, remembering to flip the sign of  the inequality for the negative

f>2  or f<-2

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Answer is b hope this helps
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Answer:

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Step-by-step explanation:

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