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2 years ago

Consider the right cones pictured below.

Mathematics

2 answers:

Vedmedyk [2.9K]2 years ago

8 0

Answer:

Step-by-step explanation:

I just took it

ella [17]2 years ago

3 0

Answer:

Step-by-step explanation:

edge 2021

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A pilot traveling 175 miles per hour encounters a head wind of 35 knots. If there are 1.15 knots per mph, what will her true spe

KonstantinChe [14]

Since one knot is 1.15 mph.
We multiply 35 time 1.15, which equals 40.25 mph.
Then we subtract. 175 - 4.25 = 134.75
Round, and you'll get 135mph
Therefore, your answer is 135mph

3 0

3 years ago

Answer is <, >, or =.

Pavlova-9 [17]

Answer:

≥

Step-by-step explanation:

6 0

2 years ago

The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the common difference of the sequence?

Maru [420]

C: 4 is the right answer

Step-by-step explanation:

Given

a1 = -3

a15 = 53

We know that explicit formula for the arithmetic sequence is:

$a_n=a_1+(n-1)d$

For the 15th, term it will be

$a_{15}=-3+(15-1)d\\53=-3+14d$

Adding 3 on both sides

$53+3 = -3+3 + 14d\\56 = 14d$

Dividing both sides by 14

$\frac{56}{14}=\frac{14d}{14}\\d=4$

Hence,

C: 4 is the right answer

Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

#LearnwithBrainly

4 0

3 years ago

According to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation, there were over 71 million wildif

suter [353]

Answer:

The probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is P=0.412.

Step-by-step explanation:

We know the population proportion π=0.8, according to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation.

If we take a sample from this population, and assuming the proportion is correct, it is expected that the sample's proportion to be equal to the population's proportion.

The standard deviation of the sample is equal to:

$\sigma_s=\sqrt{\frac{\pi(1-\pi)}{N}}=\sqrt{\frac{0.8*0.2}{500}}=0.018$

With the mean and the standard deviaion of the sample, we can calculate the z-value for 0.79 and 0.81:

$z=\frac{p-\pi}{\sigma}=\frac{0.79-0.80}{0.018} =\frac{-0.01}{0.018} = -0.55\\\\z=\frac{p-\pi}{\sigma}=\frac{0.81-0.80}{0.018} =\frac{0.01}{0.018} = 0.55$