Answer:
Jim's current weight = 119 pounds
Step-by-step explanation:
1 Stone = 14 pounds
stone = 1.5 stone
1.5 stone = 1.5 (14 pounds) = 21 pounds
Jim lost 21 pounds
Let X be Jim's Original Weight
Y be his present weight
As per given statement in the Question:
After losing 1.5 stones (21 pounds of weight) Jim now weighs Y
Present weight = original weight - 21
Y = X -21 <u> Equation 1</u>
Also Current Weight = 85 % (Original weight)
Y = 85 % (X) =
Y=
put in Equation 1
= X-21
85X = (X-21) 100
85 X = 100 X -2100
or
2100 = 100 X - 85X
2100 = 15X
or
15 X = 2100
X= 140 pounds ( Original Weight)
Current Weight = Y = Original weight - 21 <u><em>(From Equation 1)</em></u>
Y = X -21
Y = 140 -21
Y = 119 pounds (Current Weight)
<span>Given the quadratic equation: f(x) = -2x^2 - 2x - 1, the axis of symmetry can be obtained by finding the line that divides the function into two congruent or identical halves. Thus, it should pass through the vertex and is equal
to the x-coordinate of the vertex. </span>
<span>Note that a quadratic
equation in standard form: y = ax^2 + bx + c, has the vertex located at (h,k) where, h = -b/2a and k is determined by evaluating y at
h. In this case, a = -2, b = -2, thus, h = -0.5, k = 0.5. Thus, the vertex is located at (-0.5, 0.5) and the axis of symmetry is at x = -0.5. </span>
Answer:
c = 420t . . . . c is calories burned; t is hours riding at 15 mph
Step-by-step explanation:
There is not enough information given to write a function rule relating all the variables to calories burned. If we assume that calories are burned at the constant rate of 420 calories per hour, then total calories will be that rate multiplied by hours:
c = 420·t
where c is total calories burned by the 154-lb person, and t is hours riding at 15 mph.
___
In general, rates are related to quantities by ...
quantity = rate · time . . . . . where the rate is (quantity)/(time period)
The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ=
=5
n=50
s orσ =5/
=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
Learn more about probability at brainly.com/question/24756209
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There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?
No local extrema i think?
