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lianna [129]
3 years ago
14

6x2 +10x−1 discriminant

Mathematics
1 answer:
eimsori [14]3 years ago
8 0

Answer:

124

Step-by-step explanation:

6 {x}^{2} +10x−1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

{b}^{2} −4(ac)

Substitute in the values of a, b, and c.

{10}^{2} −4(6 \times (−1))

100−4(6(−1)

100−4(−6)

100 + 24

124

<h3>Hope it is helpful...</h3>

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there is a line includes the point (0,4) and has a slope of 7 what is its equation in slope-intercept form
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Answer:

y=7x+4

Step-by-step explanation:

slope- intercept form is y=mx+c

m=7

so y=7x+c

substitute (0,4) into y=7x+c

so 4=(7x0)+c

c=4

so y=7x+4

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What's 0.7 multiplied by 9<br><br> Estimate<br><br> Tell me estimation and answer in comments
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There are 321 kids on a field trip. There are 5 more girls than boys. How many girls are there? How many boys?
Ratling [72]
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3 years ago
In the figure, and bisect each other. Complete the statements to prove that quadrilateral ABCD is a parallelogram.
Alisiya [41]

Observe the figure below.

    Statement                                                                          Reason

1. AC and BD bisect each other                                             Given

2. AE = EC and BE = ED                                                         Definition of bisection

3. m \angle AEB = m \angle CED                       Vertical angle theorem

Vertical angle theorem states " When two lines intersect each other, the vertically opposite angles are always equal".

4. \Delta ABE \cong \Delta CDE                         SAS criterion for congruence

5. m \angle ACD = m \angle CAB           Corresponding angles of congruent triangles are congruent

6. AB \parallel CD                                 Converse of alternate interior angle theorem

7.  m \angle BEC = m \angle AED                   Vertical angle theorem

8.  \Delta BEC \cong \Delta DEA            SAS criterion for congruence

9.  BC \parallel AD                                 Converse of alternate interior angle theorem

As, \Delta BEC \cong \Delta DEA, so m \angle CBD = m \angle BDA as corresponding parts of corresponding triangles are equal. As these angles are alternate interior angles, so the lines BC and AD are parallel by  "Converse of alternate interior angle theorem".

5 0
3 years ago
Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.
DENIUS [597]

Answer:

The probability that a randomly chosen plate contains the number 2222 is 0.000028 approximately.

The probability that a randomly chosen plate contains the sub-string HI is 0.002548  approximately.

Step-by-step explanation:

Consider the provided information.

Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.

Part (A)

Let A is the ways in which plates consist of three letters followed by three digits and B is the ways in which two letters followed by four digits.

Here repetition is allow. The number of alphabets are 26 and the number of distinct digits are 10.

The numbers of ways in which three letters followed by three digits can be chosen is: 26\times 26\times 26 \times 10 \times 10 \times10

26^3\times 10^3=17576000

The numbers of ways in which two letters followed by four digits can be chosen is: 26\times 26\times 10 \times 10 \times 10 \times10

26^2\times 10^4=6760000

Hence, the total number of ways are 17576000 + 6760000 = 24336000

Randomly chosen plate contains the number 2222 that means the first two letter can be any alphabets but the rest of the digit should be 2222.

Thus, the total number of ways that a randomly chosen plate contains the number 2222 number are: 26^2=676

The probability that a randomly chosen plate contains the number 2222 is:

\frac{676}{24336000} \approx 0.000028

Part (B)

The number of ways in which chosen plate contains the sub-string HI:

If three letters followed by three digits plate contains the sub-string HI, then the number of possible ways are:

26\times 1\times10^3+1\times 26\times10^3

If two letters followed by four digits plate contains the sub-string HI, then the number of possible ways are:

1\times 10^4

Thus, the total number of ways that a randomly chosen plate contains the sub-string HI are:

1\times 10^4+26\times 1\times10^3+1\times 26\times10^3

62000

From part (A) we know that the total number of ways to chose a number plate is 24336000.

The probability that a randomly chosen plate contains the sub-string HI is:

\frac{62000}{24336000} \approx 0.002548

7 0
3 years ago
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