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Montano1993 [528]
3 years ago
14

help with this ASAP please

Mathematics
1 answer:
Pavel [41]3 years ago
5 0

Answer:

A'(3, 0)

B'(6, -1)

C'(2, -3)

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Using the transformation T: (x, y) (x + 2, y + 1), find the distance named.
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A(0,0) A'(2,1)
distance(AA') = √(2^2 + 1^2)
= √5
= 2.24

answer
Distance AA' = √5 or = 2.24
4 0
3 years ago
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Which expression is equivalent to (x+3)^3-9x(x+3)?
Sati [7]
The answer is: C - x^3 + 27
6 0
2 years ago
Assume the following triangles are similar. Find the scale factor and the lengths of the missing sides.
Elanso [62]

Answer:

If two figures are similar, then the correspondent sides are related by a constant factor.

For example, if the base of one side of one of the figures has a length L, then the correspondent side of the other figure has a length k*L where k is the scale factor.

Let's start with the two left triangles.

In the smaller one the base is 5, and the base of the other triangle is 15.

Then we will have:

15 = k*5

15/5 = k = 3

The scale factor is 3.

Then we will have that:

a = scale factor times the correspondent side in the smaller triangle:

a = k*3 = 3*3 = 9

a = 9

For the other two triangles, the base of the smaller triangle is 12, while the base of the larger triangle is 20.

Then we will have the relation:

12*k = 20

k = (20/12) = 10/6 = 5/3

The scale factor is 5/3

This means that the unknown side b is given by:

b*(5/3) = 15

b = (3/5)*15 = 3*3 = 9

b = 9.

5 0
3 years ago
A) The probability that you believe you will be in<br> a car accident is 25%.
olga55 [171]
The probability would be 20%
8 0
3 years ago
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A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit surv
lys-0071 [83]

Answer:

Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

            of  novels that seniors read during their time in college. An exit

            survey was conducted with a random sample of 9 seniors. The

            sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

              been met, which of the following is a 94.645% confidence

              interval for the population mean number of novels read by

              all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

                                = n - 1

                                = 9 - 1

                                = 8

⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

   =1 - 0.94645

  =0.05355 ≈ 0.05

⇒α = 0.5

Now,

\frac{\alpha}{2} = \frac{0.05}{2}

  = 0.025

Then,

t_{\frac{\alpha}{2}, df }  = 2.306

∴ we get

Population mean = x⁻ ± t_{\frac{\alpha}{2}, df } ×\frac{s}{\sqrt{n} }

                           = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

⇒Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

3 0
3 years ago
Read 2 more answers
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