Hi there,
1)
6 + (w - 10) = 5
6 + w - 10 = 5
- 4 + w = 5
w = 5 + 4
Hence, W = 9
2)
2/3 + y - 1/9 = 7/9
5/9 + y = 7/9
y= 7/9 - 5/9
Hence, Y = 2/9
4)
4x - 3/2x - 15/4 = 3/8
32x - 12x - 30 = 3
20x - 30 = 3
20x = 3 + 30
20x = 33
Hence, the answer is 33/20
5)
0.7(3s + 4) - 1.1s = 7.9
2.1s + 2.8 - 1.1 = 7.9
s + 2.8 = 7.9
s = 7.9 - 2.8
Hence, the answer is 5.1
Hope this all helps :)
Answer:
Step-by-step explanation:
Problem One
Blue = 5
Black =2
Red = 3
First of all there are 10 marbles, 2 of which are black.
That means that 8 others are not black
You can draw any one of the 8.
P(not black) = 8/10 = 4/5
Problem Two
There are 10 marbles in all
3 of them are red.
P(Red) = 3/10
Answer:
Vertex: (1, 6)
Axis of symmetry: x = 1
Step-by-step explanation:
Answer:
- Yes, They agree
Step-by-step explanation:
Do Rachel and Dylan argree?
- Yes, They agree
Prove your answer using the values of the ratio.
100 of your friends listen to it
- Total Number = 100
Rachel said the ratio of the number of the people who liked the playlist to the number of people who did not like the playlist is 75:25.
The ratio can be simplifies further by diving all through by 25;
75/25 : 25/25
3 : 1
Dylan said that for every three people who liked the playlist, one person did not.
This simplifies to 3 : 1.
Same thing with what rachel said, so they both agree
Answer:
a. z = 2.00
Step-by-step explanation:
Hello!
The study variable is "Points per game of a high school team"
The hypothesis is that the average score per game is greater than before, so the parameter to test is the population mean (μ)
The hypothesis is:
H₀: μ ≤ 99
H₁: μ > 99
α: 0.01
There is no information about the variable distribution, I'll apply the Central Limit Theorem and approximate the sample mean (X[bar]) to normal since whether you use a Z or t-test, you need your variable to be at least approximately normal. Considering the sample size (n=36) I'd rather use a Z-test than a t-test.
The statistic value under the null hypothesis is:
Z= X[bar] - μ = 101 - 99 = 2
σ/√n 6/√36
I don't have σ, but since this is an approximation I can use the value of S instead.
I hope it helps!
