C and D
Hope this helps !
First, find the slope (m) = 
= 
= 
= 
Now plug in ONE of the points and the slope into the point-slope equation:
y - y₁ = m(x - x₁); where (x₁, y₁) is the chosen point.
y - 5 = (x - 1) (I used (1,5) as the chosen point)
3(y - 5) = x - 1
3y - 15 = x - 1
3y -14 = x
-14 = x - 3y → x - 3y = -14
Answer: x - 3y = -14
Answer:
(-6,4)
Step-by-step explanation:
1/3x − 2 = x + 2 is obtained by equating the following two functions:
y = (⅓)x - 2
y = x + 2
Graph:
Draw two straight lines
1) joining (0,-2) and (6,0)
2) joining (0,2) and (-2,0)
On the graph, you'll see that the above two lines intersect at: (-6,4)
Hence the solution is (-6,4)
Answer: 14
Step-by-step explanation:
Input Data :
Point 1 (
x
A
,
y
A
) = (-4, -8)
Point 2 (
x
B
,
y
B
) = (10, -8)
Objective :
Find the distance between two given points on a line?
Formula :
Distance between two points = √
(x
B
−
x
A
)
2
+
(
y
B
−
y
A
)
2
Solution :
Distance between two points = √
(
10
− −
4
)
2
+
(
−
8
− −
8
)
2
= √
14
^2
+
0
^2
= √
196
+
0
= √
196
= 14
Distance between points (-4, -8) and (10, -8) is 14
