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Dennis_Churaev [7]
3 years ago
10

If a car is $27,000 and loses 15% of its value each year what will be the value in 5 years

Mathematics
1 answer:
Maslowich3 years ago
6 0
$27,000

10%- $2,700.
5%- $1,350.

$2,700+ $1,350 = $4,050.

$4,050 × 5 = $20,250.

$27,000 - $20,250 = $6,750.

the value will be $6,750.
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Solve ln 2 + ln x = 5. Round to the nearest thousandth, if possible.
azamat

Answer:

The  value of x nearest to thousandths is, 74.207

Step-by-step explanation:

Solve :  \ln 2 + \ln x = 5

\ln represents the logarithmic function with base e.

Using logarithmic properties:

  • \ln (mn) = \ln m + \ln n
  • \ln x = a , then x = e^a

\ln 2 + \ln x = 5

Apply the logarithmic properties; we have

\ln 2x = 5

then;

2x = e^5

or

2x=148.41315910258

Divide both sides by 2 we get;

x = 74.2065796

Therefore, the value of x nearest to thousandths is, 74.207

3 0
3 years ago
I want a correct answer you can take your time. If I was born on December 24, two thousand and four ( 24 / 12 / 2004 ) and my cl
Elden [556K]

Answer:

8 months 11 days 1 year

5 0
3 years ago
The owner of a deli recorded the number of customers who ordered each of four sandwiches available. If the deli has 50 customers
alexandr1967 [171]
160+100+180+60=500
180/500=0.36=36%
50x36%=18
That's your answer lovely~
3 0
3 years ago
Read 2 more answers
Its pretty easy if you are good at math! Please help!
aleksley [76]

Step-by-step explanation:

Explanation:

The trick is to know about the basic idea of sequences and series and also knowing how i cycles.

The powers of i will result in either: i, −1, −i, or 1.

We can regroup i+i2+i3+⋯+i258+i259 into these categories.

We know that i=i5=i9 and so on. The same goes for the other powers of i.

So:

i+i2+i3+⋯+i258+i259

=(i+i5+⋯+i257)+(i2+i6+⋯+i258)+(i3+i7+⋯+i259)+(i4+i8+⋯+i256)

We know that within each of these groups, every term is the same, so we are just counting how much of these are repeating.

=65(i)+65(i2)+65(i3)+64(i4)

From here on out, it's pretty simple. You just evaluate the expression:

=65(i)+65(−1)+65(−i)+64(1)

=65i−65−65i+64

=−65+64

=−1

So,

i+i2+i3+⋯+i258+i259=-1

8 0
3 years ago
If a = 12 and 120% of a is equal to 80\% of bthen what is a + b ?
Novosadov [1.4K]

Answer:

The answer is 30

Step-by-step explanation:

First you have to find 120% of a (12).

\frac{12}{1}  \times  \frac{120}{100}  = 14.4

Therefore; 14.4 is 80% of b, and we are trying to find 100% of b

14.4 = 80\% \\ x = 100\%

we do not know what is 100% therefore we call it *x*. In order to find this unknown value *x* we cross multiply.

14.4 \times 100\% = 80\% \times x

This is the same as saying;

14.4  \times 1 = x \times  \frac{4}{5}

100% percent would be 1 because it is the whole number we are trying to find. The 80% would be 4/5. To get 4/5 you can simply break down 80/100 ( this is 80% as a fraction).

so the new equation is: 14.4= 4/5x

We divide both sides by 4/5. Then we will get x tobe equal to 18. Therefore b is 18. We were asked to find (a + b) so.<em> </em><em>1</em><em>8</em><em>+</em><em>1</em><em>2</em><em> </em><em>=</em><em> </em><em>30</em>

4 0
2 years ago
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