a.
The polynomial w^2+18w+84 cannot be factored
The perfect square trinomial is w^2+18w + 81
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The reason the original can't be factored is that solving w^2+18w+84=0 leads to no real solutions. Use the quadratic formula to see this. The graph of y = x^2+18x+84 shows there are no x intercepts. A solution and an x intercept are basically the same. The x intercept visually represents the solution.
w^2+18w+81 factors to (w+9)^2 which is the same as (w+9)(w+9). We can note that w^2+18w+81 is in the form a^2+2ab+b^2 with a = w and b = 9
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b.
The polynomial y^2-10y+23 cannot be factored
The perfect square trinomial is y^2-10y + 25
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Using the quadratic formula, y^2-10y+23 = 0 has no rational solutions. The two irrational solutions mean that we can't factor over the rationals. Put another way, there are no two whole numbers such that they multiply to 23 and add to -10 at the same time.
If we want to complete the square for y^2-10y, we take half of the -10 to get -5, then square this to get 25. Therefore, y^2-10y+25 is a perfect square and it factors to (y-5)^2 or (y-5)(y-5)
Answer:
10x-14
Step-by-step explanation:
Answer:
1. 3sqrt(2)
Choice C
2. 2sqrt(3)
Choice D
Step-by-step explanation:
1. sqrt(x+3)
sqrt(15+3)
sqrt(18)
sqrt(9*2)
sqrt(9)sqrt(2)
3sqrt(2)
Choice C
2. 6/sqrt(x)
6/sqrt(3)
no radicals in the denominator, multiply by 1 in the form of the radical
6/sqrt(3) * sqrt(3)/sqrt(3)
6sqrt(3)/ (sqrt(3)*sqrt(3))
6sqrt(3)/3
2sqrt(3)
Choice D
You could make 15 lines and cross out 7 and see what you end up with or make a rectangle and make 14 lines so there are 15 lines/boxes then shade 7 and see how many are not shaded...... the answer is 8
Answer:
We are 95% sure that the true proportion of students that supports a fee increase is between 0.75 and 0.85.
Step-by-step explanation:
The interpretation of a x% confidence interval of proportions being between a and b is that:
We are x% sure that the true proportion of the population is between a and b.
If the 95% confidence interval estimating the proportion of students supporting the fee increase is (0.75; 0.85), what conclusion can be drawn
We are 95% sure that the true proportion of students that supports a fee increase is between 0.75 and 0.85.
