we know that
the ratio of the perimeters is equals to the scale factor
scale factor=5/8
scale factor=measure smaller square/measure larger square
let
smaller square=first square
larger square=second square
area smaller square=[scale factor]²*area larger square
so
area larger square=area smaller square/[scale factor]²
scale factor=5/8
area smaller square=225 m²
area larger square=225/[5/8]²----> 225/(25/64)-- > 225*(64/25)-----
> 576 m²
the answer is
the area of the second square (larger square) is 576
m²
In place of t, or theta, I'm going to utilize x instead. So the equation is -3*cos(x) = 1. Get everything to one side and we have -3*cos(x)-1 = 0
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
Answer:
The volume of the box is 3/4 cubic meters.
Step-by-step explanation:
We know that volume = length * width * height. We have length, width, and height already, so all we have to do is multiply.
5/6 * 1 1/8 * 4/5. First we convert 1 1/8 from a mixed fraction, to give us 9/8, as 8/8 = 1.
5/6 * 9/8 * 4/5. 5 * 9 = 45, and 6 * 8 = 48. 45/48 reduces to 15/16.
15/16 * 4/5. 15 * 4 = 60, and 16 * 5 = 80. 60/80 reduces to 6/8, which reduces to 3/4.
The lemght could be 15 because a triangle has two long sides and one short one and the two are equivalent