Some1 hurry up i need help

28 students in the class 75% pass how many students pass

SashulF [63]

Answer:

21 students pass

Step-by-step explanation:

Firstly, you can set up the problem into an equation where the variable X would equal the number of students passing. You put X over the total number of students in the class, turning it into a fraction, then set it equal to the fraction $\frac{75}{100}$ (which is 75% represented as a fraction).

$\frac{X}{28} = \frac{75}{100}$

The fraction $\frac{75}{100}$ can be simplified, because 75 and 100 are both multiples of 25, so after canceling out the 25s you would be left with $\frac{3}{4}$ .

$\frac{X}{28} = \frac{3}{4}$

Next, you use the process of cross multiplication which is essentially just multiplying the denominators of both fractions (which would be 28 and 4 in this case) to each side of the equation.

$\frac{X}{28} * 28 * 4 = \frac{3}{4} * 4 * 28$

The denominators cancel out leaving you with a simple equation to simplify.

$4* X = 3 * 28$

$4X = 84$

Finally, divide both sides by four in order to isolate the variable.

$\frac{4X}{4} = \frac{84}{4}$

X = 21.

5 0

3 years ago

The equation of a line is given below. 6x -4y = 24. Find the x-intercept and the Y-intercept then use them to graph the line

ipn [44]

Answer:

x intercept is 4 and the y intercept is -6

Step-by-step explanation:

x-int:

6x=24

x=4

y-int:

-4y=24

y=-6

5 0

4 years ago

Which system can be used to represent, x the number of tetra fish, and y, the number of goldfish, he purchased?

Fed [463]

The equation that would best describe the situation would be the first option. To solve this question, simply break down the question into sections and then use variables X and y to represent each of the things asked for in the problem. We know the following:

X = no of tetra fish
Y = no of goldfish
If there is twice as much goldfish than tetra fish, then it would be 2y.

X = 2Y.

Then knowing what X and y represent, find the equation that gives the total cost of fish he bought, knowing that 1.50 is for a goldfish and 2.00 is for a tetra fish.

7 0

3 years ago

Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams

Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0

3 years ago

What are the solutions to the system of equations <br> {-x+y=4<br> {y+12=x^2+x

Gnoma [55]

Answer:

Step-by-step explanation:

$y=4+x$ ............................................ (1)

$y=x^2+x-12$ ............................................ (2)

now equate both (1) and (2)

$4+x=x^2+x-12$

$=>x^2=16$

$x=-4,4$

now substitute the values of x ,

when $x=-4$ , y becomes 0

when $x=4$ , y becomes 8

so, solution set:

$(-4,0)$ and $(4,8)$

8 0

3 years ago