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ki77a [65]
3 years ago
5

When you flip a biased coin the probability of getting a tail is 0.6. How many times would you expect to get tails if you flip t

he coin 320 times?
Mathematics
1 answer:
laiz [17]3 years ago
4 0

Answer: I believe it’s 192 times


Step-by-step explanation:

You multiply 0.6 by 320, giving you 192


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Lim of tan(x) as x approaches pi/2. It does not ask from either the + or - direction, just pi/2. The answer is 0, but i think it
faltersainse [42]
Yes, you are right, if it approaches from the left, the limit is infinity and if it approaches from the right, the limit is negative infinity. The limit does not exist because it reaches infinity as x approaches pi/2 and the limits are the same when the value is approached from the opposite directions.
7 0
3 years ago
Solve for p<br> 3+|1+p|=12
Usimov [2.4K]
Subtract 3 from both sides

simplify 12 - 3 to 9

break down the problem into these two equations

1 + p = 9 and -(1 + p) = 9

solve the first equation 1 + p = 9 and that would be 8 since 1 + 8 = 9 is true.

solve the second equation -(1 + p) = 9 and just simplify brackets and add 1 to both sides then add 9 + 1 and lastly multiply both sides by -1 and p = -10.

Gather both solutions

Answers: p = -10, 8


5 0
3 years ago
How do you divide <br> 2 / 7367
Helen [10]

Answer:

0.00027148092

Step-by-step explanation:

calculator lol

4 0
4 years ago
Read 2 more answers
How do we round 8.373 to the nearest hundredth?
Mashutka [201]
8.373 rounded to the nearest hundredth is 8.37 because you look at the thousandths place or to the right of 7 and you see that its lower than 5 so you round down giving you the answer of 8.73

Answer: 8.73
3 0
3 years ago
I need help with 1 and 3 please
schepotkina [342]
For #1
city A's mean would be 10.5, then you would divide it by the number of numbers there is which is 5,So 10.5/5 is 2.1

city B's mean would be 11.6  then you would divide it by the number of numbers there is which is 5, So 11.6/5 is 2.32.

thats all I have don't know how to do #3 sorry 
4 0
3 years ago
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