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3 years ago

Answer number 1 and 2 am giving brainliest please help

Mathematics

2 answers:

Ymorist [56]3 years ago

5 0

9514 1404 393

Answer:

38 square inches

Step-by-step explanation:

The figure is a quadrilateral with one pair of parallel sides. That means it is a trapezoid, so the area formula for a trapezoid is applicable.

A = (1/2)(b1 +b2)h

The two parallel bases are 7 in and 12 in. The height is the perpendicular distance between them, 4 in. So, the area is ...

A = (1/2)(7 in +12 in)(4 in) = (1/2)(19 in)(4 in)

A = 38 in²

The area of the trapezoid is 38 square inches.

natali 33 [55]3 years ago

5 0

Answer:

<h2>Answer :-</h2>

We know that

The shape is trapezoid.

According to Question,

The area of trapezoid = ½(a + b) × h

a and b are parallel side of the trapezoid
H is the height of trapezoid

$\large \sf \: \dfrac{1}{2} \bigg(12 + 7 \bigg) \times 4$

$\large \sf \: 1 \times 19 \times 2$

$\large \sf \: 19 \times 2$

$\large \sf \: 38 \: in {}^{2}$

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Graph the line with 3/4 slope passing through the point (2,-2).

S_A_V [24]

Answer:

Step-by-step explanation

x1 = 2, y1 = -2 and m = 3/4

y - y1 = m(x - x1)

y - (-2) = 3/4(x - 2)

y + 2 = 3/4(x - 2)

Multiply each term by 4

4y + 8 = 3(x - 2)

4y + 8 = 3x - 6

4y = 3x - 6 - 8

4y = 3x - 14

5 0

3 years ago

Factor Trinomials:

notka56 [123]

Answer:

1. $2(x+2)(x+5)$

2. $8(x+4)^{2}$

Step-by-step explanation:

Problem #1:

1. Find the GCF (Greatest Common Factor)

$GCF = 2$

2. Factor out the GCF and simplify.

$2(x^{2} +7x+10)$

3. Factor $x^{2} +7x+10$

Which two numbers add up to 7 and multiply to 10?

2 and 5

Rewrite the expression using the above.

$(x+2)(x+5)$

4. Done!

$2(x+2)(x+5)$

Problem #2:

1. Find the GCF (Greatest Common Factor)

$GCF=8$

2. Factor out the GCF and simplify.

$8(x^{2} +8x+16)$

3. Use the perfect square formula. $a^{2} +2ab+b^{2} =(a+b)^{2}$

$a = x\\b=4$

$(x+4)^{2}$

4. Done!

$8(x+4)^{2}$

8 0

2 years ago

In how many days will the inspectors come on the same day

Jet001 [13]

Answer:

depends on situations

Step-by-step explanation:

8 0

3 years ago

Helppp me with these questions plz guys

SSSSS [86.1K]

Number 41 is letter c I think tell me if it helps you

3 0

3 years ago

A man hits a baseball when it is 4 ft above the ground with an initial velocity of 120 ft/sec. The ball leaves the bat at a 30 d

Sauron [17]

et us assume that the origin is the floor right below the 30 ft. fence

To work this one out, we'll start with acceleration and integrate our way up to position.

At the time that the player hits the ball, the only force in action is gravity where: a = g (vector)
ax = 0
ay = -g (let's assume that g = 32.8 ft/s^2. If you use a different value for gravity, change the numbers.

To get the velocity of the ball, we integrate the acceleration
vx = v0x = v0cos30 = 103.92
vy = -gt + v0y = -32.8t + v0sin40 = -32.8t + 60

To get the positioning, we integrate the speed.
x = v0cos30t + x0 = 103.92t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + 60t + 4

If the ball clears the fence, it means x = 0, y > 30

x = 0 -> 103.92 t - 350 = 0 -> t = 3.36 seconds

for t = 3.36s,
y = -16.4(3.36)^2 + 60*(3.36) + 4
= 20.45 ft

which is less than 30ft, so it means that the ball will NOT clear the fence.

Just for fun, let's check what the speed should have been :)

x = v0cos30t + x0 = v0cos30t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + v0sin30t + 4

x = 0 -> v0t = 350/cos30
y = 30 ->
-16.4t^2 + v0t(sin30) + 4 = 30
-16.4t^2 + 350sin30/cos30 = 26
t^2 = (26 - 350tan30)/-16.4
t = 3.2s

v0t = 350/cos30 -> v0 = 350/tcos30 = 123.34 ft/s

So he needed to hit the ball at at least 123.34 ft/s to clear the fence.

You're welcome, Thanks please :)

6 0

3 years ago