Answer number 1 and 2 am giving brainliest please help

Mathematics

2 answers:

Ymorist [56]2 years ago

5 0

9514 1404 393

Answer:

38 square inches

Step-by-step explanation:

The figure is a quadrilateral with one pair of parallel sides. That means it is a trapezoid, so the area formula for a trapezoid is applicable.

A = (1/2)(b1 +b2)h

The two parallel bases are 7 in and 12 in. The height is the perpendicular distance between them, 4 in. So, the area is ...

A = (1/2)(7 in +12 in)(4 in) = (1/2)(19 in)(4 in)

A = 38 in²

The area of the trapezoid is 38 square inches.

natali 33 [55]2 years ago

5 0

Answer:

<h2>Answer :-</h2>

We know that

The shape is trapezoid.

According to Question,

The area of trapezoid = ½(a + b) × h

a and b are parallel side of the trapezoid
H is the height of trapezoid

$\large \sf \: \dfrac{1}{2} \bigg(12 + 7 \bigg) \times 4$

$\large \sf \: 1 \times 19 \times 2$

$\large \sf \: 19 \times 2$

$\large \sf \: 38 \: in {}^{2}$

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Calculate the area of triangle ABC with altitude CD, given A (6,0) B(1,5) C (2,0) and D (4,2)

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So hmm check the picture below

the height or altitude is CD
and the base is AB

how long are those? well $\bf \textit{distance between 2 points}\\ \quad \\
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% (a,b)
A&({{ 6}}\quad ,&{{ 0}})\quad 
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B&({{ 1}}\quad ,&{{ 5}})\\\\
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