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Nataly [62]
3 years ago
11

If the astronaut from question #9 collides with a satellite and comes to a complete stop, where did his momentum go? Explain thi

s in terms of conservation of momentum.
Physics
1 answer:
Elis [28]3 years ago
7 0

Answer:

    m v ´- MV = (m + M) v ’

Explanation:

If the astronaut initially has a speed v the satellite has a speed V, we can define a system that is formed by the two bodies, therefore the forces during the collision are internal, so the momentum is conserved

initial instant. Before the crash

          p₀ = m v - MV

final instatne. After the crash, we have two cases

1) inelastic shock

          m_f = (m + M) v '

          p₀ = p_f

         m v ´- MV = (m + M) v ’

2) elastic collision with the astronaut's velocity, zero in this case the moment remains

        m v - MV = mv ’+ Mv’

also the kinetic energy is conserved

       mv'2 + M V2 = mv'2 + m v'2

with these two equations we can find the speed of the cars

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Sprinting near the end of a race, a runner with a mass 63 kg accelerates from a speed of 25 m/s to a speed of 26 m/s in 54 s. To
gavmur [86]

Answer:

1.1655 N

Explanation:

Given that,

Initial speed, u = 25 m/s

Final speed, v = 26 m/s

Time taken, t = 54 s

So, Applying equation of motion as:

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{26-25}{54}\ m/s^2\\\Rightarrow a=0.0185\ m/s^2

According to the Newton's second law of motion:-

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Force=63\times 0.0185\ kgm/s^2

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5 0
4 years ago
Number of protons and electrons and atomic mass for a given element
faltersainse [42]

Explanation:

You can simply subtract the atomic number from the mass number in order to find the number of neutrons. If the atom is neutral, the number of electrons will be equal to the number of protons.

Remember!

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2. Your atomic number is the amount of protons within the atom.

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5 0
3 years ago
The latent heat of vaporization of H₂O at body temperature (37°C) is 2.42 x 10⁶ J/kg. To cool the body of a 60.4-kg jogger [aver
Darya [45]

Answer:

<h2>0.094 kg</h2>

Explanation:

        Latent heat of vaporization of H_{2}O at 37°C is 2.42\times10^{6}\text{ }\frac{J}{kg}.

        When the sweat on our body evaporates, it absorbs energy from our body to overcome it's Latent heat of vaporisation. Thus our body cools down when sweat evaporates.

       So, Energy absorbed by sweat to evaporate = Energy lost by body

Specific heat capacity of human body = 3500\text{ }\frac{J}{kg\text{ }C^{o}}. Jogger weights 60.4 kg. Body temperature decreases by 1.08\text{ }C^{o}

       Energy absorbed from body = mS\Delta T=3500\times60.4\times 1.08 =228312\text{ }J

       228312\text{ }J=\text{Energy absorbed by sweat}=mC=m\times2.42\times10^{6}\\m=0.094\text{ }kg

∴ 0.094 kg of sweat has evaporated from the body.

8 0
3 years ago
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