Answer:
3658.24m
Explanation:
Hello!
the first thing that we must be clear about is that the train moves with constant acceleration
A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

Vf = final speed
=160km/h=44.4m/s
Vo = Initial speed
=42.9km/h=11.92m/s
A = acceleration
=0.25m/s^2
X = displacement
solving

the distance traveled by the train is 3658.24m
Answer: Contact the National Aeronautics and Space Association
Explanation:
The National Aeronautics and Space Association is an independent organization in US which aims to enable a safe, secure, efficient space journey and launch of new satellites, spacecraft beyond the earth's orbit. It can give better information for the space travel already conducted by the astronauts. Thus will help in writing the report as it is the best place to find the information.
thank you so much for the schlatt
The answer you are looking for is A
The length of the inclined plane is approximately 12 ft
The situation forms a right angle triangle.
<h3>Right triangle</h3>
Right triangle have one of its angle as 90 degrees.
Therefore,
The length of the inclined plane is the hypotenuse of the triangle. The length of the inclined plane can be found using trigonometric ratios.
height = 4 ft
angle(∅) = 19.45°
sin 19.45 = 4 / h
h = 4 / 0.33298412235
h = 12.0125847796
h = 12 ft
Therefore, the length of the inclined plane is approximately 12 ft
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