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soldi70 [24.7K]
3 years ago
11

If a small sports car collides head-on with a massive truck, which vehicle experiences the greater impact force? Which vehicle e

xperiences the greater acceleration? Explain your answers.
Physics
1 answer:
garri49 [273]3 years ago
5 0

Answer:

Small sports car.

Explanation:

Lets take

mass of the small car = m

mass of the truck = M

As we know that when car collide with the massive truck then due to change in the moment of the car both car as well as truck will feel force.We also know that from Third law of Newton's ,it states that every action have it reaction with same magnitude but in the opposite direction.

Therefore

F = m a

a=Acceleration of the car

a=\dfrac{F}{m}

F= M a'

a'=Acceleration of the massive truck

a'=\dfrac{F}{M}

Here given that M > m that is why a > a'

Therefore car will experiences more acceleration.

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A physical system that is isolated from its environment is:
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Closed

Explanation:

A physical system that is isolated from its environment is said to be a closed system.

In a closed system, energy can be exchange but matter cannot be exchanged.

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8 0
3 years ago
1.
ale4655 [162]

Answer:

5.0 atm

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8 0
3 years ago
A suspended object A is attracted to a charged object B, can one conclude that A is charged? Explain
irinina [24]

Explanation:

In my view, when the Object A is attracted to a Charged object B. Object B should be Negatively or Positively charged. So Object B should be the Opposite charged according to the Object B

Example =

If Object B is Negatively Charged, the Object A should be Positively Charged

If the Object B is Positively Charged, the Object A should be Negatively Charged

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5 0
3 years ago
An unknown substance has a mass of 0.125 kg and an initial temperature of 95.0°C. The substance is then dropped into a calorimet
mr Goodwill [35]

Answer:

c = 1163.34 J/kg.°C

Explanation:

Specific heat capacity:

"Specific heat capacity is the amount of heat energy required to raise the temperature of a substance per unit of mass. The specific heat capacity of a material is a physical property."

Use this equation:

mcΔT = ( mw c + mAl cAl )  ΔT'

Rearranging the equation to find the specific heat (c) you get this:

c = (( mw c + mAl cAl )  ΔT') / (mΔT)

c = (( 0.285 (4186) + (0.15)(900)) (32 -25.1)) / ((0.125) (95 - 32))

c = 1163.34 J/kg.°C

7 0
4 years ago
Read 2 more answers
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