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3 years ago

12

60 POINTS model how sound produced by a singer is recorded by a microphone and reproduced by a speaker (sound model) WITH RUBIC

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1 answer:

Nikolay [14]3 years ago

6 0

Answer:

Explanation: i don't know bro

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Imagine you are sitting on a sled and someone is about to push you down a hill. Which statement is accurate?

Dima020 [189]

The answer is:

Forces acting on the sled are paired with equal and opposite forces.

The explanation:

About to push you, this means that he doesn't push yet. If the sled is on level ground and no one is pushing it, then forces are equal and opposite.

The gravity force pulls down and the ground pushes up.

This is Newton's third law:

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

We can also see Newton’s third law at work by taking a look at how people move about. Consider a swimmer pushing off from the side of a pool.

6 0

3 years ago

Read 2 more answers

A tennis ball hits with an initial velocity of 25 m/s [10 o above the

Sav [38]

First, calculate the components of its initial velocity v0:

v0x = v0cos10 = 24.6 m/s

v0y = v0sin10 = 4.34 m/s

The ball reaches its peak when vy = 0. Let's calculate the time it takes for vy to become zero:

vy = v0y - gt ---> t = v0y/g = 0.44 s

The horizontal distance it travels in this time is

x = v0xt = (24.6 m/s)(0.44 s)

= 10.8 m

Note that the net is 15 m away. After traveling a horizontal distance of 10.8 m, the height of the ball is

y = -(1/2)gt^2 + v0yt + 2.1

= -(4.9 m/s^2)(0.44 s)^2 + (4.34 m/s)(0.44 s) + 2.1 m

= -0.95 m + 1.9 m + 2.1 m

= 3.05 m

Note that this is the height of the ball at its peak. While the ball is well above the net at its peak, it is well short of its required horizontal distance to clear it. Instead, let's find the time it takes for the tennis ball to travel a horizontal distance of 15 m first:

x = v0xt ----> t = x/v0x = (15 m)/(24.6 m/s) = 0.61 s

Then calculate the height y when t = 0.61 s. If y > 0.9 m (height of the net), then the ball will clear the net.

y = -4.9t^2 + v0yt + 2.1

= -4.9(0.61 s)^2 + (4.34 m/s)(0.61 s) + 2.1 m

= -1.82 m + 2.65 m + 2.1 m

= 2.93 m

Yes, the ball will clear the net by 2.03 m.

3 0

3 years ago

Se deja caer una pelota inicialmente en reposo desde una altura de 50m sobre el nivel del suelo. ¿cuanto tiempo requiere para ll

umka2103 [35]

Answer:

a) t = 3.2 s

b) $v_{f} = -32 m/s$

Explanation:

a) El tiempo requerido para llegar al suelo se puede calcular usando la siguiente fórmula:

$t = \sqrt{\frac{2y_{0}}{g}}$

En donde:

$y_{0}$ : es la altura inicial = 50 m

g: es la gravedad = 10 m/s²

$t = \sqrt{\frac{2y_{0}}{g}} = \sqrt{\frac{2*50 m}{10 m/s^{2}}} = 3.2 s$

Entonces, el tiempo requerido para llegar al suelo es 3.2 s.

b) La rapidez de la pelota justo antes del choque es el siguiente:

$v_{f} = v_{0} - gt$

En donde:

$v_{0}$ : es la velocidad inicial = 0 (dado que se deja caer en resposo)

$v_{f} = v_{0} - gt = 0 - 10 m/s^{2}*3.2 s = -32 m/s$

Por lo tanto, la rapidez de la pelota justo en el momento anterior del choque es -32 m/s (el signo negativo es porque la pelota está cayendo).

Espero que te sea de utilidad!

6 0

3 years ago

A local FM radio station broadcasts at a frequency of 97.3 MHz. Calculate the energy of the frequency at which they are broadcas

levacccp [35]

Answer:

6.45×10¯²⁶ J

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 97.3 MHz

Energy (E) =?

Next, we shall convert 97.3 MHz to Hz. This can be obtained as follow:

1 MHz = 1×10⁶ Hz

Therefore,

97.3 MHz = 97.3 MHz × 1×10⁶ Hz / 1 MHz

97.3 MHz = 9.73×10⁷ Hz

Thus, 97.3 MHz is equivalent to 9.73×10⁷ Hz.

Finally, we shall determine the energy at which the frequency is broadcasting. This can be obtained as follow:

Frequency (f) = 9.73×10⁷ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 9.73×10⁷

E = 6.45×10¯²⁶ J

Therefore, the energy at which the frequency is broadcasting is 6.45×10¯²⁶ J

5 0

3 years ago

5. Calculate the speed of Charlie who runs to the store 5 kilometers away in 40<br> minutes

exis [7]

This depends on what units you need to convert to, but the answer would be approximately 2.083 m/s.

5km/40min = 5000m/40min = 5000m/2400s = 2.083 m/s

7 0

3 years ago